4x+7y=47 /*4 ------>16x + 28y=188
5x-4y=-5 /*7 -------->35x-28y=-35
16x + 28y=188, add this two equations
35x-28y=-35
16x + 28y+35x-28y=188-35
16x +35x=188-35
51x =153m
x=3
5x-4y=-5
5*3-4y=-5
15-4y=-5
4y=15+5
4y=20
y=5
Answer (3,5), B
Consider one pyramid
Side length of base = 1.5cm and its height is 1 cm
Slant height of one of the lateral faces = sqrt(1^2 + 0.75^2) = 1.25 cm
Area of one of the triangular faces = 0.5 * 1.5* 1.25 = 0.9375 cm^2
There are 8 of these so the required surface area = 8 * 0.9375
= 7.5 cm^2 Answer
Answer:
b = big butt
Step-by-step explanation:
Option 3
Amount of water hold by both the pitchers (Large + small) = 12 cups
Let the small pitcher holds the water = S cups
If the water hold by the large pitcher is twice the size of the small pitcher, then the amount of water hold by large pitcher = 2S
Total amount water hold by both = S + 2S
Equation for this situation will be,
S + 2S = 12
Therefore, Option (3) will be the answer.
