Answer:
f(x) = 30 • 0.989x
Step-by-step explanation:
Given the data :
10 26.8
20 23.9
30 21.3
40 19
50 16.9
60 15.1
Using technology, the exponential model equation obtained by plotting the data is :
y = 30.068(0.989)^x
Based on the general exponential formula :
y = ab^x
y = predicted value
Initial value, a = 30.068
Rate = b = 0.989
The most appropriate model equation from the options given is :
f(x) = 30 • 0.989^x
Answer:
B) (35, 260)
Step-by-step explanation:
A veterinarian will prescribe an antibiotic to a dog based on its weight. The effective dosage of the antibiotic is given by d ≥ 1∕5w2, where d is dosage in milligrams and w is the dog's weight in pounds. Which of the following ordered pairs gives an effective dosage of antibiotics for a 35-pound dog?
A) (35, 240)
B) (35, 260)
C) (260, 35)
D) (240, 35)
Ordered pairs is composed of pairs, usually an x coordinate and a y coordinate. It refers to a location of a point on the coordinate. It matches numbers to functions or relations.
Given the relation between d is dosage in milligrams and w is the dog's weight in pounds as d ≥ 1∕5w²
For a 35 pound dog (i.e w = 35 pound). The dosage is given as:
d ≥ 1∕5(35)² ≥ 245 milligrams.
For an ordered pair (x, y), x is the independent variable (input) and y is the dependent variable (output).
The dog weight is the independent variable and the dosage is the dependent variable.
From the ordered pairs, the best option is (35, 260) because 260 ≥ 240
Answer:
15
Step-by-step explanation:
4-(-2)+3(3)
4+2+9
15
Well, if it is increasing at a fixed rate of 2 mm/s, then the volume would still be increasing at a rate of 2 mm/s when the diameter is 80 mm, if I understand your question correctly.
Answer:
Step-by-step explanation:


Volume = 
find partial derivatives using product rule

i.e.
Using maximum for partial derivatives, we equate first partial derivative to 0.
y=0 or x+y =6
x=0 or x+4y =12
Simplify to get y =2, x = 4
thus critical points are (4,2) (6,0) (0,3)
Of these D the II derivative test gives
D<0 only for (4,2)
Hence maximum volume is when x=4, y=2, z= 4/3
Max volume is = 4(2)(4/3) = 32/3