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nlexa [21]
3 years ago
11

Use the number line below, where RS = 6y +3, ST = 4y +9, and RT = 72.

Mathematics
1 answer:
timurjin [86]3 years ago
7 0

Answer:

a. 6y +3 +4y +9= 72

6y+4y+3+9=72

10y+12=72

10y=72-12

10y=60

10y/10= 60/10

y=6

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\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
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\\\\\\

\begin{cases}
\boxed{d}=5r\\
500-d=(r+10)5\\
----------\\
500-\boxed{5r}=(r+10)5
\end{cases}
\\\\\\
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