Question

I need help please!!!!

Answer 1

Let's work this problem from inside the parentheses.

($\frac{ w^{15} }{ w^{5} }$ simplifies to $w^{10}$
Now we have
$(w^{10})^{4}$ which simplifies to $w^{40}$

Final Answer: $w^{40}$

Answer 2

$\left(\dfrac{w^{15}}{w^5}\right)^4=\left(w^{15-5}\right)^4=\left(w^{10}\right)^4=w^{10\cdot4}=w^{40}\\\\\text{Answer:}\ \boxed{w^{40}}\\\\\text{Used:}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\\left(a^n\right)^m=a^{n\cdot m}$