Estimate the sum or difference of the mixed numbers in these activities. 6 13\15 + 1 4\5=
2 answers:
<h2>Fractions</h2>
Estimate the sum or difference of the mixed numbers in these activities. 6 13/15 + 1 4/5=
Let's solve the fraction part first.
- First let's find the LCD or the number that can be divided by 15 and 5. So, the LCD of 15 and 5 is 15.
- Second, let's divide the LCD (15) by the denominator of the first fraction (15) and then let's multiply the numerator of the first fraction (13) so, 15 divide by 15 is 1 times 13 is 13, the same goes for the other 15 divide by 5 is 3 times 4 is 12.
- Last let's add them, 13 plus 12 is 25 then copy the denominator.
- Simplify
- Then, combine the whole and fraction parts
Therefore, plus
is
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Answer:
(A) The 25th percentile is 20.
(B) The mean of the data set is 20 and the median of the data set is 25. The data set is left-skewed.
Step-by-step explanation:
The data set arranged in ascending order is:
S = {15, 20, 22, 25, 28, 40, 55}
(A)
Compute the 25th percentile as follows:
Thus, the 25th percentile is 20. This value implies that exactly 25% of the observations are less than 20.
(B)
Compute the sample mean as follows:
Compute the median as follows:
For a set with odd number of observations, the median value if the middle value.
The middle value is 25.
Thus, the mean of the data set is 20 and the median of the data set is 25.
The Mean < Median.
This implies that the data set is left-skewed.
Given:
Required:
To write the given equation in slope intercept form.
Explanation:
Consider
Final Answer:
Answer:
She should be expected to have 2.11 aces.
Step-by-step explanation:
I suppose there was a small typing mistake. It should be: On average she gets an ace of 8.44% of her serves.
Then
For each serve, there are only two possible outcomes. Either there is an ace, or there is not. The probability of there being an ace in a serve is independent of other serves. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
She gets an ace of 8.44% of her serves.
This means that
She attemps 25 serves:
This means that
How many aces would you expect her to have
She should be expected to have 2.11 aces.