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Nady [450]
3 years ago
5

Jose goes to the bodega. He

Mathematics
1 answer:
AysviL [449]3 years ago
3 0

Answer:

1 bag of chips cost $1.25

Step-by-step explanation:

total money spent minus cost of soda = price of 2 bags of chips

$4.00- $1.50 = $2.50

2 bags of chips divided by 2 = price for one bag

$2.50 / 2 = $1.25

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If f(x)=x+4 and g(x)=x^2-1, what is g(f(x))?
pickupchik [31]

g(f(x)) means plug in f(x) for every "x" in g(x).

g(f(x))=(x+4)^2-1=x^2+8x+16-1=x^2+8x+15

answer: x^2+8x+15

3 0
3 years ago
How do u solve -5x-10=10
umka2103 [35]
How many groups of 3 do you have
4 0
3 years ago
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In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g
KIM [24]

Answer:

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

All girls from the first group:

20 students, so N = 20

10 girls, so k = 10

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163

All girls from the second group:

20 students, so N = 20

5 girls, so k = 5

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006

All girls from the third group:

20 students, so N = 20

8 girls, so k = 8

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

7 0
3 years ago
Maria's math test had 25 questions. She got 84% correct. How many problems did she get wrong?
Art [367]
She got 4 problems incorrect
4 0
3 years ago
Decrease £2155.45 by 18.5% then rounded to 2dp
alekssr [168]

Answer:

18.5%/10×100

185

2155-185

1970

now pls round off cause I don't understand 2dp

4 0
3 years ago
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