3 years ago

Is the answer 4? because i don't know if i did this right

1 answer:

3 0

Answer:

yea no

Step-by-step explanation:

Logic. try again

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Aleksandr-060686 [28]

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Step-by-step explanation:

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jeka94

Answer: $-p^2-(q+r)^2$

Work Shown:

I'm assuming your teacher wants you to factor as much as possible.

$-p^2-q^2-r^2-2qr\\\\-p^2-q^2-2qr-r^2\\\\-p^2-(q^2+2qr+r^2)\\\\-p^2-(q+r)^2\\\\$

In the last step, I used the rule that $(a+b)^2 = a^2+2ab+b^2$

We cannot factor any further. If the first term was $p^2$ instead of $-p^2$ , then we could use the difference of squares factoring rule.

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