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Paraphin [41]
3 years ago
6

Brainiest to whoever right thanks

Mathematics
2 answers:
enot [183]3 years ago
8 0

Answer:

72 degrees

Step-by-step explanation:

Since the trees are parallel, so are the angles.

andreev551 [17]3 years ago
5 0

Answer:

18°

Step-by-step explanation:

if you draw a staight line from 2 to left tree, you get a right angled triangle with angels 72, 90 and 18. with 18degrees being at point 2.

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ASAP PLEASE
liq [111]

Answer:

Step-by-step explanation:

(4, 2)

will you brainlyest?

7 0
2 years ago
Which element is always present in a combustion reaction?
Alla [95]
Its "C" because without oxygen you can't have fire
4 0
3 years ago
Solve and check:8a-4=25+6(a-8)
OlgaM077 [116]
8a - 4 = 25 + 6 (a - 8)

(distribute the 6)

8a - 4 = 25 + 6a - 48

(combine like terms 25 - 48)

8a - 4 = 6a - 23

( subtract 6a from both sides)

2a - 4 = -23

(add 4 to both sides)

2a = -19

(divide both sides by 2)

a = - 9.5

////CHECK/////

8 (-9.5) - 4 = 25 + 6 ( -9.5 -8)

(plug each side into a calculator)

-80 = -80

FINAL ANSWER:

a = -9.5
5 0
3 years ago
Can someone help me please!!
ratelena [41]

The coordinates of E are (5.75, 0).

<h3>What is midpoint?</h3>

The midpoint is the middle point of a line segment. It is equidistant from both endpoints, and it is the centroid both of the segment and of the endpoints.

Given that, C is the midpoint of AB, D is the midpoint of CB and E is the midpoint of DB.

Formula for coordinates of midpoint,

(x, y) = [(x1+x2)/2, (y1+y2)/2]

Coordinates of C;

(x, y) = (-10+8)/2, (14-2)/2

(x, y) = (-1, 6)

Coordinates of D;

(x, y) = (-1+8)/2, (6-2)/2

(x, y) = (3.5, 2)

Coordinates of E;

(x, y) = (3.5+8)/2, (2-2)/2

(x, y) =  (5.75, 0)

Hence, The coordinates of E are (5.75, 0).

For more references on midpoints, click;

brainly.com/question/28224145

#SPJ1

8 0
1 year ago
Find the absolute maximum and absolute minimum values of the function f(x, y) = x 2 + y 2 − x 2 y + 7 on the set d = {(x, y) : |
dsp73

Looks like f(x,y)=x^2+y^2-x^2y+7.

f_x=2x-2xy=0\implies2x(1-y)=0\implies x=0\text{ or }y=1

f_y=2y-x^2=0\implies2y=x^2

  • If x=0, then y=0 - critical point at (0, 0).
  • If y=1, then x=\pm\sqrt2 - two critical points at (-\sqrt2,1) and (\sqrt2,1)

The latter two critical points occur outside of D since |\pm\sqrt2|>1 so we ignore those points.

The Hessian matrix for this function is

H(x,y)=\begin{bmatrix}f_{xx}&f_{xy}\\f_{yx}&f_{yy}\end{bmatrix}=\begin{bmatrix}2-2y&-2x\\-2x&2\end{bmatrix}

The value of its determinant at (0, 0) is \det H(0,0)=4>0, which means a minimum occurs at the point, and we have f(0,0)=7.

Now consider each boundary:

  • If x=1, then

f(1,y)=8-y+y^2=\left(y-\dfrac12\right)^2+\dfrac{31}4

which has 3 extreme values over the interval -1\le y\le1 of 31/4 = 7.75 at the point (1, 1/2); 8 at (1, 1); and 10 at (1, -1).

  • If x=-1, then

f(-1,y)=8-y+y^2

and we get the same extrema as in the previous case: 8 at (-1, 1), and 10 at (-1, -1).

  • If y=1, then

f(x,1)=8

which doesn't tell us about anything we don't already know (namely that 8 is an extreme value).

  • If y=-1, then

f(x,-1)=2x^2+8

which has 3 extreme values, but the previous cases already include them.

Hence f(x,y) has absolute maxima of 10 at the points (1, -1) and (-1, -1) and an absolute minimum of 0 at (0, 0).

3 0
3 years ago
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