3 years ago

9x + 8y3 – 7 = 3y3 -3 9x+ 5y = 0

Mathematics

1 answer:

Vikki [24]3 years ago

5 0

Answer:

102 actually just add it up

Step-by-step explanation:

add it up

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3 years ago

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Maru [420]

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Step-by-step explanation:

Remember when you divide fractions, you need to get the reciprocal of the divisor and multiply. So your first simplification would be:

$\dfrac{x^2+4x+4}{x^2-6x+8}\div\dfrac{6x+12}{3x-12}\\\\=\dfrac{x^2+4x+4}{x^2-6x+8}\times\dfrac{3x-12}{6x+12}\\\\=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}$

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$=\dfrac{(x^2+4x+4)(3x-12)}{(x^2-6x+8)(6x+12)}\\\\=\dfrac{(x+2)(x+2)(3x-12)}{(x^2-6x+8)(6(x+2))}\\\\$

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Next we factor out even more:

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And we can now simplify it to:

$=\dfrac{x+2}{2(x-2)}$

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