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2 years ago

Solve 3(4y + 6) greater equal to -2(3-6y) show work pls

Mathematics

1 answer:

horrorfan [7]2 years ago

3 0

Answer:

All real numbers

Step-by-step explanation:

See the image.

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For about $1 billion in new space shuttle expenditures, NASA has proposed to install new heat pumps, power heads, heat exchanger

11111nata11111 [884]

Answer:

The probability of one or more catastrophes in:

(1) Two mission is 0.0166.

(2) Five mission is 0.0410.

(3) Ten mission is 0.0803.

(4) Fifty mission is 0.3419.

Step-by-step explanation:

Let X = number of catastrophes in the missions.

The probability of a catastrophe in a mission is, P (X) = $p=\frac{1}{120}$ .

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}\frac{1}{120}^{x}(1-\frac{1}{120})^{n-x};\x=0,1,2,3...$

In this case we need to compute the probability of 1 or more than 1 catastrophes in n missions.

Then the value of P (X ≥ 1) is:

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

$=1-{n\choose 0}\frac{1}{120}^{0}(1-\frac{1}{120})^{n-0}\\=1-(1\times1\times(1-\frac{1}{120})^{n-0})\\=1-(1-\frac{1}{120})^{n-0}$

(1)

Compute the compute the probability of 1 or more than 1 catastrophes in 2 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{2-0}=1-0.9834=0.0166$

(2)

Compute the compute the probability of 1 or more than 1 catastrophes in 5 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{5-0}=1-0.9590=0.0410$

(3)

Compute the compute the probability of 1 or more than 1 catastrophes in 10 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{10-0}=1-0.9197=0.0803$

(4)

Compute the compute the probability of 1 or more than 1 catastrophes in 50 missions as follows:

$P(X\geq 1)=1-(1-\frac{1}{120})^{50-0}=1-0.6581=0.3419$

6 0

3 years ago

Please help

Slav-nsk [51]

Answer:

8x+12

Step-by-step explanation:

Remember that perimeter is all the sides combined. A rectangle has the same length and width for both sides.

P=2l+2w

P=2(4x-6)+2(12)

P=8x-12+24

P=8x+12

8 0

3 years ago

Read 2 more answers

Which statement is true about the graphed function?

yarga [219]

Answer: Choice D)

F(x) > 0 over the inverval (-infinity, -4)

Translation: The y or f(x) values are positive whenever x < -4.

========================================================

Further Explanation:

Recall that y = f(x), so if we say something like f(x) < 0 then we mean y < 0. Choice A is false because points on the curve to the left of x = -4 have positive y coordinates. Similar reasoning applies to choice B as well.

Choice C is false because while the interval (-infinity, -4) is above the x axis, the portion from x = -4 to x = -3 is below the x axis.

Choice D is true because everything to the left of x = -4 is above the x axis. Pick any point on the blue curve that is to the left of x = -4. This point will be above the horizontal x axis. Keep in mind that the parenthesis notation attached to the -4 means we dont include -4 as part of the interval.

4 0

3 years ago

Read 2 more answers

Please help me with 1-4

asambeis [7]

well ik the angle of 1 and 2 are right angles and number 4 is 180° but I'm not sure ab number 2 sorry i.d.k if I helped someone might be able to explain better and help

5 0

3 years ago

Can you pls help me the quiz is timed noo links and can you give me an explanation

Shtirlitz [24]

Answer:

2 and 96 (lowest and highest #s far from any other #s listed

7 0

3 years ago