It looks like you're asked to find the value of y(-1) given its implicit derivative,
and with initial condition y(2) = -1.
The differential equation is separable:
Integrate both sides:
Solve for y :
![y = -\dfrac1{\sqrt[3]{3x+C}}](https://tex.z-dn.net/?f=y%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3x%2BC%7D%7D)
Use the initial condition to solve for C :
![y(2) = -1 \implies -1 = -\dfrac1{\sqrt[3]{3\times2+C}} \implies C = -5](https://tex.z-dn.net/?f=y%282%29%20%3D%20-1%20%5Cimplies%20-1%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3%5Ctimes2%2BC%7D%7D%20%5Cimplies%20C%20%3D%20-5)
Then the particular solution to the differential equation is
![y(x) = -\dfrac1{\sqrt[3]{3x-5}}](https://tex.z-dn.net/?f=y%28x%29%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3x-5%7D%7D)
and so
![y(-1) = -\dfrac1{\sqrt[3]{3\times(-1)-5}} = \boxed{\dfrac12}](https://tex.z-dn.net/?f=y%28-1%29%20%3D%20-%5Cdfrac1%7B%5Csqrt%5B3%5D%7B3%5Ctimes%28-1%29-5%7D%7D%20%3D%20%5Cboxed%7B%5Cdfrac12%7D)
The graph g(x) is Steeper.
Answer: 6a 2(a+2a) and the last one
Step-by-step explanation:
Answer:
True, based on the <em>Transitive Property of Equality</em>.
Step-by-step explanation:
Note that the <em>Transitive Property of Equality </em>states that "If a = b, & b = c, then a = c.
In this case it is the same.
∠1 ≅ ∠2 (because both are complementary), ∠1 ≅ ∠3 (again, both are complementary), then based on the Transitive Property, ∠2 ≅ ∠3, making all of them complementary angles
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<em>~Senpai</em>
Answer:
Is the answer, if you want it simplified then, 
Step-by-step explanation:
