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inna [77]
3 years ago
10

The base of an isosceles right triangle is 30 cm. What is its area?

Mathematics
1 answer:
dlinn [17]3 years ago
7 0

Answer:

A = 450 cm²

Step-by-step explanation:

Since the right triangle is isosceles then the 2 logs are congruent , both 30 cm and at right angles to each other.

The area (A ) of the triangle is calculated as

A = \frac{1}{2} bh ( b is the base and h the perpendicular height )

Here b = h = 30 , then

A = \frac{1}{2} × 30 × 30 = \frac{1}{2} × 900 = 450 cm²

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3 years ago
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you deposit 10,000 in an account that pays 3% annual interest compounded monthly. How much will you have in 5 years?
Inessa [10]

Answer:

$2,833.59

Step-by-step explanation:

1 $10,000.00 $10,000.00 $511.64 $0.00 $10,511.62 $10,000.00

2 $10,000.00 $10,511.62 $537.79 $0.00 $11,049.41 $10,000.00

3 $10,000.00 $11,049.41 $565.30 $0.00 $11,614.72 $10,000.00

4 $10,000.00 $11,614.72 $594.23 $0.00 $12,208.95 $10,000.00

5 $10,000.00 $12,208.95 $624.63 $0.00 $12,833.59 $10,000.00

8 0
3 years ago
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A square pyramid has a base length of 4 inches. The height of each triangular face is 12 inches. What is the surface area of the
Wittaler [7]

Answer:

The surface area of the given pyramid is 112 inches^{2}.

Step-by-step explanation:

Base length of the pyramid = 4 inches

Area of the base = length^{2}

                            = 4^{2}

                            = 16

Area of its base = 16 inches^{2}

Area of one of its triangular surface = \frac{1}{2} x base x height

                                 = \frac{1}{2} x 4 x 12

                                 = 2 x 12

                                 = 24 inches^{2}

Area of all its four triangular surfaces = 4 x 24

                                                       = 96 inches^{2}

surface area of the pyramid = sum of areas of all its surfaces

                                               = 16 + 96

                                       = 112 inches^{2}

The surface area of the given pyramid is 112 inches^{2}.

8 0
3 years ago
Dr. Mann mixed 9.357 g of chemical A, 12.082 g of chemical B, and 7.502 g of chemical C to make 5 doses of medicine. About how m
SOVA2 [1]

Answer:

Step-by-step explanation:

.

1) About how much medicine did he make in grams?

Dr. Mann mixed

9.357 g of chemical A,

12.082 g of chemical B,

7.502 g of chemical C

We can determine total amount of medicine that was prepared by Dr. Mann by summing up the chemicals (A,B,C)

=( 9.357grams of A + 12.082grams of B+ 7.502grams of C)

= 28.941 grams in total

The next step is to round up those chemicals value to their nearest tenth as asked by question

Dr. Mann mixed

9.357 g of chemical A= 9.4grams

12.082 g of chemical B,=12.1grams

7.502 g of chemical C =7.5grams

2)Estimate the amount of each chemical by rounding to the nearest tenth of a gram before finding the sum.

Then the sum after rounding up to nearest tenth is

(9.4grams +12.1grams + 7.5grams)

=29 gram

7 0
3 years ago
I need to find the x pls help and show work
grigory [225]

Answer:

77

Step-by-step explanation:

84/12=7

so

7*11= 77

4 0
3 years ago
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