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inna [77]
2 years ago
10

The base of an isosceles right triangle is 30 cm. What is its area?

Mathematics
1 answer:
dlinn [17]2 years ago
7 0

Answer:

A = 450 cm²

Step-by-step explanation:

Since the right triangle is isosceles then the 2 logs are congruent , both 30 cm and at right angles to each other.

The area (A ) of the triangle is calculated as

A = \frac{1}{2} bh ( b is the base and h the perpendicular height )

Here b = h = 30 , then

A = \frac{1}{2} × 30 × 30 = \frac{1}{2} × 900 = 450 cm²

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Quantity of Jackets Price (in whole dollars) Total Revenue Marginal Revenue Total Cost Marginal Cost Profit (or loss) 0 20 1 20
KonstantinChe [14]

Answer:

18 dollars

Step-by-step explanation:

Marginal cost can be defined as the additional cost to produce every additional unit of a certain good. In mathematical terms;

Marginal cost = change in cost / change in quantity

For seven jackets, we have to find the difference between the cost of seven jackets and the cost of six jackets as follows

$101 - $83 = $18

Since the change in quantity is one, our marginal cost comes to $18.

3 0
3 years ago
Andrea needs a box that has a volume of 90 cubic inches what might the measures of her box be
Eduardwww [97]
Volume is Length x width x height. So what are three numbers that multiply to 90?
30x30x30=90
8 0
3 years ago
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What is the solution to the equation below? riund your answer to two decimal places. (24) log(3x) = 60
Amanda [17]

The answer is:  " x = 105.41 " . 

_____________________________________________

Explanation:

_____________________________________________

Given:   " 24 log (3x) = 60 " ;  Solve for "x" .

The default is to assume "base 10" for the "logarithm". 

_____________________________________________

Start by dividing each side of the equation by "24" ; 

       →   [ 24 log(3x) ] / 24  = 60 / 24 ; 

to get:  

_____________________________________________

 log (3x)  = 2.5 ;

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Rewrite as:  log₁₀ (3x) = 2.5 ;  

_____________________________________________

Using the property of logarithms:

⇔    10⁽²·⁵⁾  =   3x  ;  

↔   3x = 10⁽²·⁵⁾   ;

         →  10^ (2.5) = 316.2277660168379332 ;

     →  3x = 316.227766016837933 ;  

Divide each side of the equation by "3" ;

  to isolate "x" on one side of the equation;

      and to solve for "x" ;

    →  3x / 3 =  316.2277660168379332 / 3  ;

to get:

    →   x = 105.4092553389459777333 ;

    →  round to 2 (two) decimal places;

_____________________________________________

         →   " x = 105.41 " .

_____________________________________________

 Hope this helps!

    Best wishes to you!

_____________________________________________

8 0
3 years ago
Find e^cos(2+3i) as a complex number expressed in Cartesian form.
ozzi

Answer:

The complex number e^{\cos(2+31)} = \exp(\cos(2+3i)) has Cartesian form

\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2).

Step-by-step explanation:

First, we need to recall the definition of \cos z when z is a complex number:

\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}.

Then,

\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}. (I)

Now, recall the definition of the complex exponential:

e^{z}=e^{x+iy} = e^x(\cos y +i\sin y).

So,

e^{2i-3} = e^{-3}(\cos 2+i\sin 2)

e^{-2i+3} = e^{3}(\cos 2-i\sin 2) (we use that \sin(-y)=-\sin y).

Thus,

e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)

Now we group conveniently in the above expression:

e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2.

Now, substituting this equality in (I) we get

\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2.

Thus,

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right].

5 0
3 years ago
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Hoochie [10]

Answer:

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Step-by-step explanation:

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105° + 11° = 2x

116°= 2x

Divide both sides by 2

X = 58°.

4 0
2 years ago
Read 2 more answers
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