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Harman [31]
3 years ago
6

If the hypotenuse of a right triangle is 11 and one leg is 2, what is the length of the other leg?

Mathematics
2 answers:
son4ous [18]3 years ago
6 0

Answer:

I think its 10.82

Step-by-step explanation:

if its a right triangle you have to you pythogrus thiurum

Lelu [443]3 years ago
5 0

Answer:

Step-by-step explanation:

So 11 times 2=22 so you times 11 times 2 on all sides so the answers is 22

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Step-by-step explanation:

4 0
3 years ago
How should I go about solving this question?
Verdich [7]

Answer:

A radius of a circle or sphere is any of the line segments from its center to its perimeter, and in more modern usage, it is also their length

Step-by-step explanation:

3 0
2 years ago
5. The length of a rectangular swimming pool is 50 yards, and the width of the pool is 16
d1i1m1o1n [39]
The answer is C. I got this by doing a^2 + b^2= c^2. 50^2 + 16^2=c^2, 2500 + 256 = c^2, 2756 = c^2, then you take the square root of 2756 and that gives you your answer 52.50 yards. Hope this helps :D
7 0
2 years ago
At a raffle, 1500 tickets are sold at $2 each. There are four prizes given for $500, $250, $150, and $75. You buy one ticket. Us
wolverine [178]

Answer:

<u>The expected value of every ticket is a loss of $ 1.35</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of tickets sold at the raffle = 1,500

Price of each ticket = $ 2

Total prizes = 1 * $ 500 + 1 * $ 250 + 1 * $ 150 + 1 * $ 75

2. Use a probability distribution table to calculate the expected value of your gain. Your expected value is_____ ?

Let's answer the question using a probability distribution for the gains, this way:

  • Probability of 1st prize of $ 498 (500 - ticket) = 1/1,500
  • Probability of 2nd prize of $ 248 (250 - ticket) = 1/1,500
  • Probability of 3rd prize of $ 148 (150 - ticket) = 1/1,500
  • Probability of 4th prize of $ 73 (75 - ticket) = 1/1,500
  • Probability of losing $ 2 (ticket) = 1,496/1,500

Now, we calculate the mean for all the tickets (winners and non-winners), this way:

Expected value = [(1,496 * -2) + (1 * 498) + (1 * 248) + ( 1 * 148) + ( 1 * 73)]/1,500

Expected value = [- 2,992 +498 + 248 + 148 + 73)/1,500

Expected value = -2,025/1,500 = - 1,35

<u>The expected value of every ticket is a loss of $ 1.35</u>

8 0
3 years ago
SOMEONE PLEASE HELP HURRY (show work pls
ycow [4]
Answer is b. -1/2
worked it out in the pic

5 0
3 years ago
Read 2 more answers
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