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2 years ago

If the hypotenuse of a right triangle is 11 and one leg is 2, what is the length of the other leg?

Mathematics

2 answers:

son4ous [18]2 years ago

6 0

Answer:

I think its 10.82

Step-by-step explanation:

if its a right triangle you have to you pythogrus thiurum

Lelu [443]2 years ago

5 0

Answer:

Step-by-step explanation:

So 11 times 2=22 so you times 11 times 2 on all sides so the answers is 22

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2 years ago

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What is the minimum number of months' worth of living expenses that should be in an emergency fund?

horsena [70]

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3 years ago

8x+5=6x+19. Help me pleaseeeeeeeeeee

hammer [34]

Answer:

7x=12

Step-by-step explanation:

8x+5=6x+19

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2 years ago

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To get a student learner's permit to drive in New Jersey, an individual must be at least 16 years old. Let, a, represent the age

vredina [299]

Answer:

$a\geq 16$

Step-by-step explanation:

Let $a$ represents the age at which a person gets a student learner's permit to drive in New Jersey.

Also, an individual must be at least $16$ years old to get a student learner's permit to drive in New Jersey.

So, inequality is $a\geq 16$

(Inequality explains a relationship of greater than or greater than or equal to or less than, or less than or equal to between two mathematical expressions)

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2 years ago

I can't figure out how to do (i + j) x (i x j)for vector calc

Vinil7 [7]

In three dimensions, the cross product of two vectors is defined as shown below

$\begin{gathered} \vec{A}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} \\ \vec{B}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k} \\ \Rightarrow\vec{A}\times\vec{B}=\det (\begin{bmatrix}{\hat{i}} & {\hat{j}} & {\hat{k}} \\ {a_1} & {a_2} & {a_3} \\ {b_1} & {b_2} & {b_3}\end{bmatrix}) \end{gathered}$

Then, solving the determinant

$\Rightarrow\vec{A}\times\vec{B}=(a_2b_3-b_2a_3)\hat{i}+(b_1a_3+a_1b_3)\hat{j}+(a_1b_2-b_1a_2)\hat{k}$

In our case,

$\begin{gathered} (\hat{i}+\hat{j})=1\hat{i}+1\hat{j}+0\hat{k} \\ \text{and} \\ (\hat{i}\times\hat{j})=(1,0,0)\times(0,1,0)=(0)\hat{i}+(0)\hat{j}+(1-0)\hat{k}=\hat{k} \\ \Rightarrow(\hat{i}\times\hat{j})=\hat{k} \end{gathered}$

Where we used the formula for AxB to calculate ixj.

Finally,

$\begin{gathered} (\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=(1,1,0)\times(0,0,1) \\ =(1\cdot1-0\cdot0)\hat{i}+(0\cdot0-1\cdot1)\hat{j}+(1\cdot0-0\cdot1)\hat{k} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=1\hat{i}-1\hat{j} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=\hat{i}-\hat{j} \end{gathered}$

Thus, (i+j)x(ixj)=i-j

8 0

11 months ago