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valina [46]
2 years ago
15

The temperature was 30 degrees. The temperature dropped 50 degrees. Then the temperature increased 5 degrees. What is the temper

ature now?
Mathematics
1 answer:
RUDIKE [14]2 years ago
7 0

Answer:

-15 degrees

Step-by-step explanation:

In order to get what I answered you first subtract 50 from 30 then you get -20 then it says the temperature increased by 5 so you add 5 to -20 and get -15. Also I don't know if it is in celcius or Fahrenheit but if that's all its asking then it should be right.

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What is the turning point of the graph of f(x) = |x| + 4 ?
leva [86]
F(x) = |x| + 4

f(0) = I 0 I + 4===> (0,4)

f(0) = - 0 +4 ===> (0,4)
3 0
2 years ago
The value of a house has increased by 5% the house is now valued at £609000 what is the value of the house before the increase?
lutik1710 [3]

Answer:

Current \ price = 609000\\\\Let \ the \ original \ price \ be = x\\\\\% increase = 5 \% \ of \ x = \frac{5}{100} \times x = \frac{5x}{100}\\\\Price \ after \ increase, current\ price = \frac{5x}{100} + x\\\\

=> 609000 = \frac{5x}{100} + x\\\\=>609000 = \frac{105x}{100}\\\\=> x = \frac{609000 \times 100}{105}\\\\x = 580000

Therefore original price = $580,000

3 0
2 years ago
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
mariarad [96]

Answer:

What would you like help with?

Step-by-step explanation:

6 0
2 years ago
use the discriminant to determine how many and what kind of solutions the quadratic equation x²-x=-1/4 has
pantera1 [17]

\bf x^2-x=-\cfrac{1}{4}\implies \stackrel{\textit{multiplying by }\stackrel{LCD}{4}}{4x^2-4x=-1}\implies 4x^2-4x+1=0


\bf \qquad \qquad \qquad \textit{discriminant of a quadratic} \\\\\\ \stackrel{\stackrel{a}{\downarrow }}{4}x^2\stackrel{\stackrel{b}{\downarrow }}{-4}x\stackrel{\stackrel{c}{\downarrow }}{+1} ~~~~~~~~ \stackrel{discriminant}{b^2-4ac}= \begin{cases} \boxed{0}&\textit{one solution}\\ positive&\textit{two solutions}\\ negative&\textit{no solution} \end{cases} \\\\\\ (-4)^2-4(4)(1)\implies 16-16\implies \boxed{0}

4 0
3 years ago
COMPRÉ 30 LIBROS A 40 BS CADA UNO ; VENDÍ UNOS CUANTOS A 360 BS, A 36 BS CADA UNO. ¿ EN CUANTO DEBO VENDER CADA UNO DE LOS RESTA
Ksenya-84 [330]

Answer:

28BS

Step-by-step explanation:

Compré 30 libros a 40 bs cada uno;

Precio de costo = 30 × 40BS

= 1200 BS

Vendí unos pocos a 360 Bs, a 36 Bs cada uno.

Número de libros vendidos = 360 BS / 36 BS

= 10 libros

Número de libros restantes = 40 BS - 10 BS

= 30 BS

¿Cuánto debo vender cada uno de los libros restantes para no perder ni ganar nada?

Para no ganar ni perder nada, la cantidad total que queda para vender los libros =

1200BS - 360 BS = 840 BS

La cantidad para vender cada uno de los libros restantes sin ganar ni perder nada se calcula como:

840BS / Número de libros restantes

= 840BS / 30BS

= 28BS

8 0
2 years ago
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