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Basile [38]
3 years ago
14

1. Given the points (-2,4) and (4, -2), find the midpoint between these points.

Mathematics
1 answer:
Naddika [18.5K]3 years ago
5 0

Answer:

(1,1)

Step-by-step explanation:

M=(x1+x2 / 2 , y1+y2 / 2)

M=(-2+4 / 2 , 4+ -2 / 2)

M=(2 / 2 , 2 / 2)

M=(1,1)

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If f ( x ) = 2 x - 5, then f (4) is _____.<br><br> 3<br> 5<br> 4<br> 17
ICE Princess25 [194]
The answer is 3

if you substitute x as 4 then it would be 2 x 4 = 8

8-5=3
7 0
2 years ago
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Suppose you want to estimate the proportion of traditional college students on your campus who own their own car. From research
Lapatulllka [165]

Answer:

2,655 students

Step-by-step explanation:

The z-score for a 99% confidence interval is z = 2.576

The standard error for a proportion p is:

SE = z*\sqrt{\frac{p*(1-p)}{n} }

For a proportion of p =0.20, in order to ensure a standard error of 0.02, the sample size 'n' must be:

0.02 = 2.576*\sqrt{\frac{0.2*(1-0.2)}{n}}\\n=2,654.31

Rounding up to the next whole student, the sample size needed is 2,655 students.

5 0
2 years ago
Which one is it A, B, C, or D?
Molodets [167]
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8 0
2 years ago
Which statement is true about the extreme value of the given quadratic equation? y = -3x2 + 12x − 33
Zina [86]

Answer:

The equation has a maximum value with a y-coordinate of -21.

Step-by-step explanation:

Given

y =-3x^2 + 12x - 33

Required

The true statement about the extreme value

First, write out the leading coefficient

Leading = -3

-3 < 0 means that the function would be a downward parabola;

Downward parabola always have their vertex on top of the parabola and as such, the function has a maximum value.

The maximum value is:

x = -\frac{b}{2a}

Where:

a= -3; b =12; c =-33

So, we have:

x = -\frac{12}{2 * -3}

x = -\frac{12}{-6}

x =2

Substitute x =2 in y =-3x^2 + 12x - 33

y = -3*2^2 + 12 * 2 - 33

y = -21

<em>Hence, the maximum is -21.</em>

8 0
3 years ago
Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select t
nignag [31]

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

On the other hand we have that if two lines are perpendicular, then the product of their slopes is -1. So:

m_ {1} * m_ {2} = - 1

The given line is:

5x-2y = -6\\-2y = -6-5x\\2y = 5x + 6\\y = \frac {5} {2} x + \frac {6} {2}\\y = \frac {5} {2} x + 3

So we have:

m_ {1} = \frac {5} {2}

We find m_ {2}:m_ {2} = \frac {-1} {\frac {5} {2}}\\m = - \frac {2} {5}

So, a line perpendicular to the one given is of the form:

y = - \frac {2} {5} x + b

We substitute the given point to find "b":

-4 = - \frac {2} {5} (5) + b\\-4 = -2 + b\\-4 + 2 = b\\b = -2

Finally we have:

y = - \frac {2} {5} x-2

In point-slope form we have:

y - (- 4) = - \frac {2} {5} (x-5)\\y + 4 = - \frac {2} {5} (x-5)

ANswer:

y = - \frac {2} {5} x-2\\y + 4 = - \frac {2} {5} (x-5)

3 0
3 years ago
Read 2 more answers
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