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Anna007 [38]
3 years ago
7

can someone please please help with this?? i’m stuck on it and no one is helping me. it’s really late and it’s the only thing i

need to do right now so this might be a spam:( sorry but thank you guys so so much ur really helpful i had so much homework today <3 take your time!

Mathematics
1 answer:
Reika [66]3 years ago
5 0

Answer:

  M   HTH   TTH   TH   H   T   T   .   t   h   th

1. 6      5        6       2     4   2   5       5  6   2

2. 2     4         5       1     5   2   3       2  5   2

3.        3         5       6     2   3   5       1   2   0

4.        8         2       0     6   0   3       0  5   6

Step-by-step explanation:

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Joe drove 530 miles in hours 15 minutes. What was his average speed pee hour?
scZoUnD [109]
530 divided by 15 is 35.3
4 0
3 years ago
Mathematical Q PRACTICE Use Number Sense A puppy weighs 12 ounces What fractional part of a pound is this A
Lisa [10]
Do 12/16 which equals 0.75
0.75 is equal to 3/4
so the answer is 3/4


Hope this helps!
8 0
3 years ago
A card is drawn from a standard deck. Find the probability of drawing a heart or a 7.
Mazyrski [523]
<h3>Answer:   4/13</h3>

=======================================================

Explanation:

There are A = 13 hearts and B = 4 copies of "7"

The count A+B = 13+4 = 17 may seem like it's the count of hearts or "7" cards, but we're double counting the 7 of hearts. So the true count is actually 17-1 = 16

There are 16 cards we want (either a heart or a "7") out of 52 total. Therefore, the probability is 16/52 = (4*4)/(4*13) = 4/13

6 0
3 years ago
33. Suppose you were on a planet where the
tatyana61 [14]

<u>Answer:</u>

a) 3.675 m  

b) 3.67m

<u>Explanation:</u>

We are given acceleration due to gravity on earth =9.8ms^-2

And on planet given = 2.0ms^-2

A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula  </u>

\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}

Where H = max jump height,  

v0 = velocity of jump,  

Ø = angle of jump and  

g = acceleration due to gravity

Considering velocity and angle in both cases  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)  

g1 = 2.0ms^-2 and  

g2 = 9.8ms^-2

Substituting these values we get H1 = 3.675m which is the required answer

B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by  </u>

 \mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}

which is due to projectile motion of ball  

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,  

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write  

\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0ms^-2  and g2 = 9.8ms^-2

We get h1 = 3.67m which is the required height

6 0
4 years ago
Dababy (yeah yeah) (lets gooooo)
nydimaria [60]
Hey besty *bites bottom lip*



7 0
3 years ago
Read 2 more answers
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