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3 years ago

Draw the reflection of the quadrilateral across the x-axis.

Mathematics

2 answers:

Sauron [17]3 years ago

7 0

9514 1404 393

Answer:

see attached

Step-by-step explanation:

Each point moves to a position as far below the x-axis as the original point is above the x-axis. The x-coordinate remains unchanged.

Dafna11 [192]3 years ago

6 0

Answer:

Points:

x = 1, y = -3

x = 2, y = -6

x = 6, y = -7

x = 7, y = -1

Basically just make sure that all x-coordinates stay the same (positive), while y-coordinates are in opposite signs (negative)

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Ad libitum [116K]

The slope is - 2/3

The Y-Intercept is - 1

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3 years ago

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A hole is drilled in a sheet-metal component, and then a shaft is inserted through the hole. The shaft clearance is equal to dif

VashaNatasha [74]

Answer:

(A)

$P(X \geq 0.8) = \int\limits_{0.8}^{\infty} f(x) \, dx = \int\limits_{0.8}^{1} 1.25(1-x^4) \, dx = 0.08192$

(B)

Then the cumulative function would be

$CF(x) = 1.25x - 0.25x^5$ if 0<x<1

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Step-by-step explanation:

(A)

We are looking for the probability that the random variable X is greater than 0.8.

$P(X \geq 0.8) = \int\limits_{0.8}^{\infty} f(x) \, dx = \int\limits_{0.8}^{1} 1.25(1-x^4) \, dx = 0.08192$

(B)

For any $x$ you are looking for the probability $P(X \geq x)$ which is

$P(X \geq x) = \int\limits_{-\infty}^{x} 1.25(1-t^4) dt = \int\limits_{0}^{x} 1.25(1-t^4) dt = 1.25x - 0.25x^2$

Then the cumulative function would be

$CF(x) = 1.25x - 0.25x^5$ if 0<x<1

0 otherwise.

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4 years ago

Maggie just worked a week for Jan's Jewels. Her pay before deductions was $98.28 and she worked 18 hours.

solniwko [45]

Answer:

$5.46

Step-by-step explanation:

You would take $98.28 and divide it by 18 and the answer would be $5.46

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Answer:

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