Answer:
n=-3/4
Step-by-step explanation:
Answer:
0.6988
Step-by-step explanation:
Given that the number of people who use the ATM at night outside your local bank branch can be modeled as a Poisson distribution.
Let X be the number of customers arriving between 10 and 11 am.
X is Poisson with mean= 1.2
Required probability
= the probability that in the hour between 10 and 11 PM at least one customer arrives
= P(X≥1)
=1-P(X=0)
=1-0.3012
= 0.6988
Are you trying to simply the equation if so x = 6
<span>#include <iostream>
using namespace std;
class InventoryTag {
public:
InventoryTag();
int getQuantityRemaining() const;
void addInventory(int numItems);
private:
int quantityRemaining;
};
InventoryTag::InventoryTag() {
quantityRemaining = 0;
}
int InventoryTag::getQuantityRemaining() const {
return quantityRemaining;
}
void InventoryTag::addInventory(int numItems) {
if (numItems > 10) {
quantityRemaining = quantityRemaining + numItems;
}
}
int main() {
InventoryTag redSweater;
int sweaterShipment = 0;
int sweaterInventoryBefore = 0;
sweaterInventoryBefore = redSweater.getQuantityRemaining();
sweaterShipment = 25;
cout << "Beginning tests." << endl;
// FIXME add unit test for addInventory
/* Your solution goes here */
cout << "Tests complete." << endl;
return 0;
}</span>
Mean
add up numbers and divide by how many there are
(1+1+5+3+6+6)/7=3 and 2/3
