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zzz [600]
2 years ago
5

Can someone help me get this please???

Mathematics
1 answer:
jarptica [38.1K]2 years ago
5 0

Answer:

With respect to the reference angle, one leg is the adjacent leg, or the leg right next to the reference angle; and the other leg is the opposite leg, or the leg on the opposite side of the triangle. If two triangles are similar, the ratios of corresponding sides are equal.

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Which ordered pair is a solution of the equation? 5x-2y=18
irakobra [83]

Answer:

(2, -4)

Step-by-step explanation:

I did some research.

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<Jayla>

3 0
2 years ago
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(03.01 LC)
vampirchik [111]

Answer:

√7 units, √98 units

Step-by-step explanation:

Pythagorean theorem

a^2+b^2=c^2. So 9+b^2=16. So b^2=7. So b=√7

a^2+b^2=c^2. SO 49+49=c^2. So 98=c^2. So c=√98.

4 0
2 years ago
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Recall that Rn denotes the right-endpoint approximation using n rectangles, Ln denotes the left-endpoint approximation using n r
pogonyaev

Answer:

R_5=1.12

Step-by-step explanation:

We want to calculate the right-endpoint approximation (the right Riemann sum) for the function:

f(x)=x^2+x

On the interval [-1, 1] using five equal rectangles.

Find the width of each rectangle:

\displaystyle \Delta x=\frac{1-(-1)}{5}=\frac{2}{5}

List the <em>x-</em>coordinates starting with -1 and ending with 1 with increments of 2/5:

-1, -3/5, -1/5, 1/5, 3/5, 1.

Since we are find the right-hand approximation, we use the five coordinates on the right.

Evaluate the function for each value. This is shown in the table below.

Each area of each rectangle is its area (the <em>y-</em>value) times its width, which is a constant 2/5. Hence, the approximation for the area under the curve of the function <em>f(x)</em> over the interval [-1, 1] using five equal rectangles is:

\displaystyle R_5=\frac{2}{5}\left(-0.24+-0.16+0.24+0.96+2)= 1.12

3 0
2 years ago
Find the volume of the following compound shape.<br>​
Bess [88]
<h3>Given:</h3>
  • Cone
  • Cylinder
<h3>Volume of the cone:</h3>

v =  \frac{1}{3} \pi {r}^{2} h

v =  \frac{1}{3}  \times \pi \times  {10}^{2}  \times 10

v = 1047.20 \:  {cm}^{3}

<h3>Volume of the cylinder:</h3>

v = \pi {r}^{2} h

v = \pi \times  {10}^{2}  \times 10

v = 3141.59 \:  {cm}^{3}

<h3>Total volume:</h3>

v = 1047.20 + 3141.59

v = 4188.79 \:  {cm}^{3}

<u>Hence</u><u>,</u><u> </u><u>the</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>cone</u><u> </u><u>shape</u><u> </u><u>is</u><u> </u><u>4188.7</u><u>9</u><u> </u><u>cubic</u><u> </u><u>centimeters</u><u>.</u>

5 0
1 year ago
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In how many years will the interest of a sum of rs 3600 at the rate of 5.5% per year be rs 594?​
boyakko [2]

Answer:

In 3 years, the interest of a sum of rs 3600 at the rate of 5.5% per year be Rs 594.

Step-by-step explanation:

T = ?

R = 5.5%

P = Rs 3600

I = Rs 594

so

T = (I×100)/(P×R)

or, T = (594×100)/(3600×5.5)

or, T = 59400/19800

so, T = 3 yrs

7 0
2 years ago
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