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Basile [38]
2 years ago
10

Suppose that Paolo and Sharon are the only consumers of ice cream cones in a particular market. The following table shows their

monthly demand schedules: Price Paolo’s Quantity Demanded Sharon’s Quantity Demanded (Dollars per cone) (Cones) (Cones) 1 8 16 2 5 12 3 3 8 4 1 6 5 0 4 On the following graph, plot Paolo’s demand for ice cream cones using the green points (triangle symbol). Next, plot Sharon’s demand for ice cream cones using the purple points (diamond symbol). Finally, plot the market demand for ice cream cones using the blue points (circle symbol). Note: Line segments will automatically connect the points. Remember to plot from left to right. Paolo’s Demand Sharon’s Demand Market Demand 0 4 8 12 16 20 24 6 5 4 3 2 1 0 PRICE (Dollars per cone) QUANTITY (Cones)
Mathematics
1 answer:
Rudiy272 years ago
4 0
Suppose that Paolo and Sharon are the only consumers of ice cream cones in a particular market. The following table shows their monthly demand schedules: Price Paolo’s Quantity Demanded Sharon’s Quantity Demanded (Dollars per cone) (Cones) (Cones) 1 8 16 2 5 12 3 3 8 4 1 6 5 0 4 On the following graph, plot Paolo’s demand for ice cream cones using the green points (triangle symbol). Next, plot Sharon’s demand for ice cream cones using the purple points (diamond symbol). Finally, plot the market demand for ice cream cones using the blue points (circle symbol). Note: Line segments will automatically connect the points. Remember to plot from left to right. Paolo’s Demand Sharon’s Demand Market Demand 0 4 8 12 16 20 24 6 5 4 3 2 1 0 PRICE (Dollars per cone) QUANTITY (Cones)
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This is the answer for this question

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Point Q' is the image of Q(-4, 7) under a translation by 4 units to the right and 2 units down.
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Answer:

Q' ( 0,5)

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x+4

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3 years ago
Evaluate the integral by making an appropriate change of variables.
VARVARA [1.3K]

By inspecting the integrand, the "obvious" choice for substitution would be

<em>u</em> = <em>y</em> + <em>x</em>

<em>v</em> = <em>y</em> - <em>x</em>

<em />

Solving for <em>x</em> and <em>y</em>, we would have

<em>x</em> = (<em>u</em> - <em>v</em>)/2

<em>y</em> = (<em>u</em> + <em>v</em>)/2

in which case the Jacobian and its determinant are

J=\begin{bmatrix}x_u&x_v\\y_u&y_v\end{bmatrix}=\dfrac12\begin{bmatrix}1&-1\\1&1\end{bmatrix}\implies|\det J|=\left|\dfrac12\right|=\dfrac12

The trapezoid <em>R</em> has two of its edges on the lines <em>x</em> + <em>y</em> = 8 and <em>x</em> + <em>y</em> = 9, so right away, we have 8 ≤ <em>u</em> ≤ 9.

Then for <em>v</em>, we observe that when <em>x</em> = 0 (the lowest edge of <em>R</em>), <em>v</em> = <em>y</em> ; similarly, when <em>y</em> = 0 (the leftmost edge of <em>R</em>), <em>v</em> = -<em>x</em>. So

-<em>x</em> ≤ <em>v</em> ≤ <em>y</em>

-(<em>u</em> - <em>v</em>)/2 ≤ <em>v</em> ≤ (<em>u</em> + <em>v</em>)/2

-<em>u</em> + <em>v</em> ≤ 2<em>v</em> ≤ <em>u</em> + <em>v</em>

-<em>u</em> ≤ <em>v</em> ≤ <em>u</em>

<em />

So, the integral becomes

\displaystyle\iint_R5\cos\left(7\frac{y-x}{y+x}\right)\,\mathrm dA=\int_8^9\int_{-u}^u\frac52\cos\left(\frac{7v}u\right)\,\mathrm dv\,\mathrm du

=\displaystyle\frac52\int_8^9\frac u7(\sin7-\sin(-7))\,\mathrm du

=\displaystyle\frac57\sin7\int_8^9u\,\mathrm du

=\displaystyle\frac5{14}\sin7(9^2-8^2)=\boxed{\frac{85}{14}\sin7}

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3 years ago
What place value was the number rounded<br> .546 to .55
tatyana61 [14]
The hundredths place value was rounded.
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