When the base of a triangle is fixed at 2.218 millimeters, the area will be 0.1098 mm².
<h3>What will the area be?</h3>
It should be noted that the area of a triangle is calculated as:
Area of triangle = (1/2)×base×height
= (1/2) × 2.218 mm × 0.099 mm
= 1.109 mm × 0.099 mm
= 0.109791 mm²
≈ 0.1098 mm²
Therefore, the <em>area</em> is 0.1098 mm².
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The base of a triangle is fixed at 2.218 millimeters. Determine the number of
significant figures of the area of the triangle with each given height of 0.099mm.
Answer:
see explanation
Step-by-step explanation:
Calculate C by adding corresponding components of A + B
C = ![\left[\begin{array}{ccc}4\\-7.5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C-7.5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}-2.5\\5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2.5%5C%5C5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}4-2.5\\-7.5+5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4-2.5%5C%5C-7.5%2B5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}1.5\\-2.5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1.5%5C%5C-2.5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
I would say it would look something like this: 3k - 3 = g? That would be my best guess. I hope I helped & I'm so sorry if I'm wrong!
Answer:
f(x) = 9(5/3)^x
Step-by-step explanation:
f(x) = a(b^x)
x = 0
9 = a(b⁰)
9 = a
f(x) = 9(b^x)
x = 1
15 = 9(b¹l
b = 15/9
b = 5/3
f(x) = 9(5/3)^x
