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3 years ago

Find the gradient of this line. Use gradient = rise/run

Mathematics

1 answer:

Marysya12 [62]3 years ago

5 0

Step-by-step explanation:

the gradient of the line = 2 units/ 3 units = 2/3

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D) IfA: B = 1 : 2 and A: C= 2:3, find B: C.

DaniilM [7]

Answer:

it's 2/3

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8 0

3 years ago

How to write y-6=-5/2 (x+4)

coldgirl [10]

Answer:

In point slope form, this is y = (-5/2)x + 2. In standard form, it's (5/2)x + y = 2.

Step-by-step explanation:

y-6=-5/2 (x+4) has already been written in point-slope form. The slope of the line is -5/2 and the point on the line is (-4,6).

In slope-intercept form: add 6 to both sides of the original equation, obtaining y = 6 - (5/2)(x + 4), or y = 2 - (5/2)x, or y = (-5/2)x + 2

8 0

3 years ago

What are the 4-factor pairs of 56?

nika2105 [10]

Answer:

7 and 8, 2 and 28, 1 and 56, 4 and 14

Step-by-step explanation:

4 0

3 years ago

Carleen has 104 pieces of candy leftover from Halloween. She would like to distribute them evenly to the 8 kids on her block. Wr

algol13

Answer:

8x = 104

x = 13

Step-by-step explanation:

Since we are trying to distribute it evenly, we divide 104 by 8 to get 13 pieces of candy per child.

The equation is saying 8 kids times <em>x</em> amount of candy per kid is equal to a total amount of 104 pieces of candy.

4 0

3 years ago

Read 2 more answers

Give the following equations determine if the lines are parallel perpendicular or neither

GaryK [48]

In order to determine whether the equations are parallel, perpendicular, or neither, let's simply each equation into a slope-intercept form or basically, solve for y.

Let's start with the first equation.

$\frac{6x-5y}{2}=x+1$

Cross multiply both sides of the equation.

$6x-5y=2(x+1)$ $6x-5y=2x+2$

Subtract 6x on both sides of the equation.

$6x-5y-6x=2x+2-6x$ $-5y=-4x+2$

Divide both sides of the equation by -5.

$-\frac{5y}{-5}=\frac{-4x}{-5}+\frac{2}{-5}$ $y=\frac{4}{5}x-\frac{2}{5}$

Therefore, the slope of the first equation is 4/5.

Let's now simplify the second equation.

$-4y-x=4x+5$

Add x on both sides of the equation.

$-4y-x+x=4x+5+x$ $-4y=5x+5$

Divide both sides of the equation by -4.

$\frac{-4y}{-4}=\frac{5x}{-4}+\frac{5}{-4}$ $y=-\frac{5}{4}x-\frac{5}{4}$

Therefore, the slope of the second equation is -5/4.

Since the slope of each equation is the negative reciprocal of each other, then the graph of the two equations is perpendicular to each other.

5 0

1 year ago