Question

SUPER URGENT: Complete the general form of the equation of a sinusoidal function having an amplitude of 6, a period of 2pi/3, and a phase shift to the left 1 unit.
y =

Answer 1

Answer:

A general sinusoidal equation is:

y = A*sin(w*x + p) + M

where:

A is the amplitude

w is the angular frequency

p is the phase shift

M is the midline.

Now, we know that:

Amplitude must be 6, so A = 6

period is 2*pi/3

Remember that the frequency is the inverse of the period, then:

f = 1/T

f = 1/(2*pi/3) = 3/(2*pi)

And the angular frequency is 2*pi times the normal frequency, then:

w = 2*pi*f = 2*pi*(3/2*pi) = 3

w = 3

Here we not have information about the midline, so M = 0.

And we know that the phase shift is one unit to the left.

Remember horizontal translations:

for a function f(x), an horizontal translation of N units is written as:

g(x) = f(x + N)

if N > 0, then the translation is to the left

if N < 0 , then the translation is to the right,

Here we know that the phase shift is to the left, so p must be positive, and we know that the shift is 1 unit to the left, then:

p = +1

Replacing these in the equation we get:

y = 6*sin(3*x + 1) + 0

y = 6*sin(3*x + 1)