3 years ago

Find the solution of each equation using the given replacement set please help ASAP

Mathematics

1 answer:

sertanlavr [38]3 years ago

5 0

Answer:

Sorry I don't know this answer

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Anestetic [448]

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Step-by-step explanation:

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3 years ago

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Kruka [31]

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4 years ago

Some Quadratic functions <br>I desperately need some help

Daniel [21]

Answer:

$\large\boxed{0=3x^2+2x-2}\\\\\boxed{0=-3x+3x^2-2}\\\\\boxed{0=-1x-2+3x^2}$

Step-by-step explanation:

$\text{The quadratic equation:}\\\\ax^2+bx+c=0\\\\a-coefficient\\\\c-constant\ term\\\\\text{We have}\ coefficient\ a=3\ \text{and}\ constant\ term\ c=-2.\\\\\text{Therefore the equation is:}\\\\3x^2+bx-2=0\\3x^2-2+bx=0\\bx+3x^2-2=0\\bx-2+3x^2=0\\-2+3x^2+bx=0\\-2+bx+3x^2=0$