im pretty sure that it is
i
Given :
a-b = c-d ...1)
b = d-1 ...2)
c = 6
To Prove :
a = 5
Solution :
Adding equation 1 and 2, we get :
(a-b) + (b) = (c-d) + (d-1)
a = c -1 ...3)
Putting given value of c = 6 in above equation, we get :
a = 6 - 1
a = 5
Hence, proved.
Q(3) = -2(3)+2 = -4
r(q(3)) = (-4)^2-1 = 15
Answer:
2.88
Step-by-step explanation:
not much to explain here l/mao
I believe its 27 cause u have to multiply 3 times 3 which is 9, then 3 times 9 which is 27
