Answer:
16 people
Step-by-step explanation:
This is a set problem
let first session be a
let second session be b
128 people attended at least one session = a∪b
a. 3/4 attended both session 1&2 = a∩b
b. 7/8 attended session 2 = p(b) i.e population b
c x attended session 1 = p(a) i.e. population a
lets get the figures.
- For both sessions 3/4 × 128 = 96 = a∩b
- For second session 7/8 × 128 = 112 = b
- The formular is a∪b = p(a) + p(b) - a∩b
- a∪b = 128 (they at least one session)
lets substitute into the equation
let p(a) be x
128 = x + 112 - 96
128 = x + 16
x = 112 - no of people that attended the morning session.
But to find those that ONLY attended morning session
x - a∩b
112 - 96 = 16
Answer:
3.72 answer is your answer
f(n) = -6.5n + 14.5
&
f(1) = 8, f(n+1) = f(n) - 6.5
So we have to find out what x is before we can solve for either angle
because vertical angles are always congruent we can set the two equations to equal each other and solve for x
so
-3x + 58 = x - 2
we need to get all the x terms on one side before we can solve for x so let's add 2 to both sides to get x alone on the right side
now we have
-3x + 60 = x
now we add 3x to both sides
60 = 4x
we isolated the terms and now we can solve for x by dividing both sides by 4
15 = x
so if x = 15 we need to plug that in to both equations to check our work
C = -3(15) + 58
C = 13
D = 15 - 2
D = 13
x does in fact equal 15 because both equations got the same answer and we found out that angle D = 13
