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Masteriza [31]
3 years ago
14

Question 14

Mathematics
1 answer:
Delicious77 [7]3 years ago
8 0

Answer:

A (5,6)

Step-by-step explanation:

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If you continue adding fractions according to this pattern when will you reach a sum of 2?
mr Goodwill [35]

Answer:

You will never be able to reach the sum of 2

Step-by-step explanation:

6 0
2 years ago
How do you find a vector that is orthogonal to 5i + 12j ?
Rashid [163]
\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies  -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\

\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies  -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
\\\\\\
\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}&#10;\\\\\\&#10;\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}&#10;\\\\\\&#10;\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}
4 0
3 years ago
Find the simple interest earned to the nearest cent for each principal, interest rate, and time.
Y_Kistochka [10]

Answer:

Interest earned at 3.9 percent rate is $31.2

Interest earned at 2 percent rate is $5.8

Step-by-step explanation:

A = P(1 + rt)

Where 'A' is the amount, 'r' is the rate and 't' is the time in years

When;

P = $1200

r = 3.9%

t = \frac{8}{12} years

Then,

A = $1200(1 + 0.039(\frac{8}{12}))

A = $1200 + $31.2 = $1231.2

Interest = Amount - Principal

Interest earned at 3.9 percent rate is $1231.2 - $1200 = $31.2

When;

P = $580

r = 2%

t = \frac{6}{12} years

Then,

A = $580(1 + 0.02(\frac{6}{12}))

A = $580 + $5.8 = $585.8

Interest earned = Amount - Principal

Interest earned at 2 percent rate = $585.8 - $580 = $5.8

4 0
3 years ago
The perimeter of pqrs is 84. Find the length of each side qr=3(rs)
kramer
Pq= 10.5, qr=31.5, rs=10.5, sp=31.5
3 0
3 years ago
Solve this pls <br> 5) 3x6-4=?
lina2011 [118]

Answer:

5

Step-by-step explanation:

Use PEMDAS to complete the problem

PE doesn't matter, there's not parentheses or exponents

MD=Multiplication and Division. Do 3*6=9, now your problem looks like 9-4

AS=Addition and Subtraction. 9-4=5

4 0
1 year ago
Read 2 more answers
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