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Mrac [35]
3 years ago
7

Which equation would demonstrate the commutative property?

Mathematics
1 answer:
kompoz [17]3 years ago
7 0

Answer:

b. 37 • 26 = 26 • 37

:)))))))))))))))))))

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1+2+3+4+5+6+7+8+9+1+2+3+4+5+6+7+8+9+10 times 2
Maksim231197 [3]

Answer:

200

Step-by-step explanation:

<u>Step 1:  Add</u>

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10

1 + 2 = 3

3 + 3 = 6

6 + 4 = 10

10 + 5 = 15

15 + 6 = 21

21 + 7 = 28

28 + 8 = 36

36 + 9 = 45

45 + 1 = 46

46 + 2 = 48

48 + 3 = 51

51 + 4 = 55

55 + 5 = 60

60 + 6 = 66

66 + 7 = 73

73 + 8 = 81

81 + 9 = 90

90 + 10 = 100

<em>100</em>

<u>Step 2:  Multiply</u>

100 * 2

<em>200</em>

Answer:  200

6 0
3 years ago
I need help I don’t get this someone help.
Andrei [34K]

Answer:

A,C,D

...............................

4 0
3 years ago
Read 2 more answers
What is the slope of the line that passes through the points (13,-8) and (-11,4)
pogonyaev

Answer:

- \frac{1}{2}

Step-by-step explanation:

Find slope using the slope formula : \frac{y2-y1}{x2-x1}

Plug in the given points : \frac{4- (-8)}{-11-13}

Add the numbers : \frac{12}{-11-13}

Calculate the difference : \frac{12}{-24}

Reduce the fraction : -\frac{1}{2}

Solution : -\frac{1}{2}

3 0
3 years ago
A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739
OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
  2. <em>Then for the x direction</em> it is known that the initial velocity is v_{0x} = 5320 m/s, the acceleration (the applied by the engine) in x direction is a_{x} 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the  is 739 s. Then: v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}
  3. In the same fashion, <em>for the y direction</em>, the initial velocity is  v_{0y} = 0 m/s, the acceleration in y direction is a_{y} 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}
8 0
3 years ago
A milk container's capacity is one gallon. How many cups would be equal?
Butoxors [25]
<span>there are 16 cups in one gallon</span>
5 0
3 years ago
Read 2 more answers
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