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VashaNatasha [74]
2 years ago
7

When you sketch a figure of an adult male, it is recommended that the head be 1/8 of the total height. If the full drawn height

of a 6-foot man is 16 inches, how many inches should the drawing of his head be from top to bottom? FYI: It says High school math but it's middle school.
Mathematics
1 answer:
luda_lava [24]2 years ago
3 0

Answer:

Maybe two inches

Step-by-step explanation:

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Tap on the photo pls help
DerKrebs [107]

Answer:

49

Step-by-step explanation:

5^2 - 4(-3)(2)

5^2 - 4(-6)

25 - 4(-6)

25 - (-24)

49

Hope this helps!

8 0
3 years ago
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Solve the proportion ASAP do both promblem
lakkis [162]

8. 1/3 = 3/y

or, y= 9

11. 3/x= 6/x+8

or, 6x=3x+24

or, 3x= 24

or, x=8

Hope it helps uh.

6 0
2 years ago
Read 2 more answers
(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2
Montano1993 [528]

Answer:

\dfrac{m^3}{16p^2q^2}

Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

m^{-1}=\dfrac{1}{m}

2.

q^0=1

3.

2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}

4.

(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}

5.

m^{-1}=\dfrac{1}{m}

6.

2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

7.

\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

8 0
3 years ago
(9-2x)+(6x+4) find the sum
aliya0001 [1]

Answer:

4x+13

Step-by-step explanation:

combine like terms -2x and 6x to get 4 then combine 9 and 4 to get 13

8 0
3 years ago
which expression correctly shows the commutative proberty? a)8+14+22+9=(8+14)+(22+9). b)8+14+22+9=8+(14+22)+9. c)8+14+22+9=53. d
Lerok [7]
D has the commutative property because it just flip flopped the numbers.
5 0
3 years ago
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