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yKpoI14uk [10]
2 years ago
8

Rita owed her brother $15 after her birthday she was able to pay him back and still had $45 how much money did Rita receive for

her birthday
Mathematics
1 answer:
cricket20 [7]2 years ago
6 0

Answer: 60

Step-by-step explanation:

-15+60=45

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Please show the working and answer. you can take a picture for the working.
baherus [9]

Answer:

(a) The area of the triangle is approximately 39.0223 cm²

(b) ∠SQR is approximately 55.582°

Step-by-step explanation:

(a) By sin rule, we have;

SQ/(sin(∠SPQ)) = PQ/(sin(∠PSQ)), which gives;

5.4/(sin(52°)) = 6.8/(sin(∠PSQ))

∴ (sin(∠PSQ)) = (6.8/5.4) × (sin(52°)) ≈ 0.9923

∠PSQ = sin⁻¹(0.9923) ≈ 82.88976°

Similarly, we have;

5.4/(sin(52°)) = SP/(sin(180 - 52 - 82.88976))

Where, 180 - 52 - 82.88976 = ∠PQS = 45.11024

SP = 5.4/(sin(52°))×(sin(180 - 52 - 82.88976)) ≈ 4.8549

Given that RS : SP = 2 : 1, we have;

RS = 2 × SP = 2 × 4.8549 ≈ 9.7098

We have by cosine rule, \overline {RQ}² =  \overline {SQ}² +  \overline {SR}² - 2 × \overline {SQ} × \overline {SR} × cos(∠QSR)

∠QSR and ∠PSQ are supplementary angles, therefore;

∠QSR = 180° - ∠PSQ = 180° - 82.88976° = 97.11024°

∠QSR = 97.11024°

Therefore;

\overline {RQ}² =  5.4² +  9.7098² - 2 ×  5.4×9.7098× cos(97.11024)

\overline {RQ}² ≈ 136.42

\overline {RQ} = √(136.42) ≈ 11.6799

The area of the triangle = 1/2 ×\overline {PQ} × \overline {PR} × sin(∠SPQ)

By substituting the values, we have;

1/2 ×\overline {PQ} × \overline {PR} × sin(∠SPQ)

1/2 × 6.8 × (4.8549 + 9.7098) × sin(52°) ≈ 39.0223 cm²

The area of the triangle ≈ 39.0223 cm²

(b) By sin rule, we have;

\overline {RS}/(sin(∠SQR)) = \overline {RQ}/(sin(∠QSR))

By substituting, we have;

9.7098/(sin(∠SQR)) = 11.6799/(sin(97.11024))

sin(∠SQR) = 9.7098/(11.6799/(sin(97.11024))) ≈ 0.82493

∠SQR = sin⁻¹(0.82493) ≈ 55.582°.

8 0
3 years ago
The function f(x) = { x + 1 is used to complete this Which statements are true of the given function? Check all that apply. tabl
Dmitry [639]

Answer:

Options (1) and (5)

Step-by-step explanation:

Expression that defines the function is,

f(x)=\frac{1}{2}x+\frac{3}{2}

Option 1

f(-\frac{1}{2})=\frac{1}{2}(-\frac{1}{2})+\frac{3}{2}

          =-\frac{1}{4}+\frac{3}{2}

          =-\frac{1}{4}+1+\frac{1}{2}

          =1+\frac{1}{4}

          =1\frac{1}{4}

So, f(-\frac{1}{2} )=-2 is false.

Option 2

f(0) = \frac{1}{2}(0)+\frac{3}{2}

     = \frac{3}{2}

True.

Option 3

f(1) = \frac{1}{2}(1)+\frac{3}{2}

    = \frac{3+1}{2}

    = 2

Therefore, f(1) = -1 is false.

Option 4

f(2)=\frac{1}{2}(2)+\frac{3}{2}

       =1+1+\frac{1}{2}

       =2\frac{1}{2}

Therefore, f(2) = 1 is false.

Option 5

f(4) =\frac{1}{2}(4)+\frac{3}{2}

     =2+\frac{3}{2}

     =\frac{4+3}{2}

     =\frac{7}{2}

True.

Options (1) and (5) are the correct options.

5 0
3 years ago
What is the area of the largest rectangle that can be inscribed in an isosceles triangle with side lengths $8$, $\sqrt{80}$, and
e-lub [12.9K]
First let's solve the general case for an isosceles triangle of base 2 and height k. If the triangle is drawn so the base is on the x-axis and the apex is on the y-axis, the equation for the line containing the right side is
  y = -k(x-1)
Then a rectangle with x-dimension w will have an area that is the product of this width and the height y = -k((w/2)-1).
  area = w(-k(w/2 -1)) = (-k/2)w² +kw
The derivative of area with respect to w will be zero where the area is a maximum:
  d(area)/dw = 0 = -kw +k
  w = 1 . . . . . . add kw and divide by k
Using the formula for area, we find
  area = 1(-k(1/2-1)) = k/2
This value is 1/2 the total area of the triangle we started with.

If the side lengths of your triangle are 8, √80, and √80, the height will be given by the Pythagorean theorem as
  h = √((√80)² - (1/2·8)²) = √(80-16) = 8
Your triangle's area will be
  triangle area = (1/2)(8)(8) = 32

The maximum area of the inscribed rectangle will be half this value,
  16 square units

4 0
3 years ago
What is the perimeter of the triangle below? Round to the nearest hundredth.
hoa [83]
I think - 14 or 14 but I am not sure.
3 0
3 years ago
8. Mark chose a number between 0.437 and 0.436 and multiplied it by 4. Then, he
Dvinal [7]

Answer:

y=¾(4x-20)

y=3x-15

Final answer= y - 3(x+12)

=y - 3x-36

=3x-15-3x-36

= -51

5 0
3 years ago
Read 2 more answers
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