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max2010maxim [7]
3 years ago
10

Problem: 4 × 32 + 8 ÷ 2 - (5 + 3)

Mathematics
2 answers:
oksian1 [2.3K]3 years ago
8 0

Answer:

124

Step-by-step explanation:

4 x 32 = 128

128 + 8 divided 2 - (5 + 3 )

divide 8 and 2 = 4

128 + 4 - ( 5 + 3)

add 5 + 3 = 8

128 + 4 - 8

<u><em>Answer: 124 </em></u>

lubasha [3.4K]3 years ago
6 0

Answer:

124

Step-by-step explanation:

is in the photo

i hope this helps :)

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Kendall recently received a job offer which required him to move his house full of furniture across the country from Columbia, S
astra-53 [7]
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1092                                 109
671                                    67
985                                    99

Relation, x/y = 1092/109 = 10.02
671/67 = 10.2
So, Relation is  x = 10.02y

Hope this helps!
3 0
3 years ago
PLEASE HELP !!!!!10 POINTS Please show steps and explain how to get answer <br><br> Solve (x-5)+3=7
Thepotemich [5.8K]
(x-5)+3=7
-3          -3
(x-5) = 4
x-5 = 4
+5     +5
x=9
6 0
4 years ago
Read 2 more answers
1. Alyssa is twice as old as Brittany, and Jazmin is 15 years older than Alyssa. If Jazmin is 45 years old, how old is Brittany?
luda_lava [24]

Answer:

Brittany is 15 years old

Step-by-step explanation:

The way we get the answer is by getting the age of Alyssa 45-15=30 as, Jazmin is 15 years older than Alyssa and then we can see that Alyssa is twice as old as Brittany so we divide Alyssa's age by two. 30÷2=15 and we get Brittany's age which is 15 years old.

7 0
3 years ago
Read 2 more answers
A positive real number is 4 less than another. If the sum of the squares of the two numbers is 72, then find the numbers.
Illusion [34]

Answer:

Our two numbers are:

2+4\sqrt{2} \text{ and } 4\sqrt{2}-2

Or, approximately 7.66 and 3.66.

Step-by-step explanation:

Let the two numbers be <em>a </em>and <em>b</em>.

One positive real number is four less than another. So, we can write that:

b=a-4

The sum of the squares of the two numbers is 72. Therefore:

a^2+b^2=72

Substitute:

a^2+(a-4)^2=72

Solve for <em>a. </em>Expand:

a^2+(a^2-8a+16)=72

Simplify:

2a^2-8a+16=72

Divide both sides by two:

a^2-4a+8=36

Subtract 36 from both sides:

a^2-4a-28=0

The equation isn't factorable. So, we can use the quadratic formula:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = 1, <em>b</em> = -4, and <em>c</em> = -28. Substitute:

\displaystyle x=\frac{-(-4)\pm\sqrt{(-4)^2-4(1)(-28)}}{2(1)}

Evaluate:

\displaystyle x=\frac{4\pm\sqrt{128}}{2}=\frac{4\pm8\sqrt{2}}{2}=2\pm4\sqrt{2}

So, our two solutions are:

\displaystyle x_1=2+4\sqrt{2}\approx 7.66\text{ or } x_2=2-4\sqrt{2}\approx-3.66

Since the two numbers are positive, we can ignore the second solution.

So, our first number is:

a=2+4\sqrt{2}

And since the second number is four less, our second number is:

b=(2+4\sqrt{2})-4=4\sqrt{2}-2\approx 3.66

6 0
3 years ago
Read 2 more answers
Help again because i suck
sukhopar [10]

Answer:

the answer should be 4x

Step-by-step explanation:

i apoligize if i'm wrong

8 0
3 years ago
Read 2 more answers
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