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s344n2d4d5 [400]
3 years ago
15

Find and simplify the difference quotient of the form

a%7D%20%2C%20x%5Cneq%20a" id="TexFormula1" title="\fra\frac{f(x)-f(a)}{x-a} , x\neq a" alt="\fra\frac{f(x)-f(a)}{x-a} , x\neq a" align="absmiddle" class="latex-formula">
f(x)=3x^2+x ,a =4

What is the difference quotient?
Mathematics
2 answers:
spayn [35]3 years ago
8 0

If f(x)=3x^2+x, then

f(4) = 3\cdot4^2+4 = 52

so that the difference quotient is

\dfrac{f(x)-f(a)}{x-a} = \dfrac{3x^2+x-52}{x-4}

Factorize the numerator:

3x^2+x-52 = (3x+13)(x-4)

Then for <em>x</em> ≠ 4, we have

\dfrac{f(x)-f(a)}{x-a} = \dfrac{(3x+13)(x-4)}{x-4} = 3x+13

Ilia_Sergeevich [38]3 years ago
6 0

Answer: 3x + 13

Step-by-step explanation:

f(x)=3x^2+x\\f(a)=3a^2+a\\f(4)=3*4^2+4=52\\\\f(x)-f(4)=3x^2+x-52=(x-4)(3x+13)\\\\\dfrac{f(x)-f(4)}{x-4} =\dfrac{3x^2+x-52}{x-4} \\\\if\ x \neq 4\ then \\\\\dfrac{f(x)-f(4)}{x-4} =\dfrac{(x-4)(3x+13)}{x-4} \\\\=3x+13\\

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