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xz_007 [3.2K]
2 years ago
12

Hugh has to earn at least $400 to meet his fundraising goal he only has 100 books that he plans to sell at $8 each. Which inequa

lity shows the number of books, x, Hugh can sell at his goal? (9th-grade Algebra 1)

Mathematics
1 answer:
bezimeni [28]2 years ago
3 0

Answer:

The revenue in the problem is equal to $400 that is to be made out of 100 books selling at $8 each. The minimum number of books he has to seel is $400/$8 per book of 50 books. The maximum number is 100 books. Hence the answer to this problem is 50 ≤ x ≤ 100.

Step-by-step explanation:

The revenue in the problem is equal to $400 that is to be made out of 100 books selling at $8 each. The minimum number of books he has to seel is $400/$8 per book of 50 books. The maximum number is 100 books. Hence the answer to this problem is 50 ≤ x ≤ 100.

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Sophia had 64¢ until she spent 1 quarter. How much money does Sophia have now?
aleksklad [387]

Answer:

Sophia now has 39 cents.

Step-by-step explanation:

One quarter = 25 cents

Since Sophia had 64 cents until she spent 25 cents (1 quarter).

So we subtract 25 cents from 64 cents.

\:  \:  \: 64 \: cents \\  \frac{ - 25 \: cents}{ \:  \:  \: 39 \: cents}

Therefore, Sophia now has 39 cents.

7 0
3 years ago
How is this solved using trig identities (sum/difference)?
GenaCL600 [577]
FIRST PART
We need to find sin α, cos α, and cos β, tan β
α and β is located on third quadrant, sin α, cos α, and sin β, cos β are negative

Determine ratio of ∠α
Use the help of right triangle figure to find the ratio
tan α = 5/12
side in front of the angle/ side adjacent to the angle = 5/12
Draw the figure, see image attached

Using pythagorean theorem, we find the length of the hypotenuse is 13
sin α = side in front of the angle / hypotenuse
sin α = -12/13

cos α = side adjacent to the angle / hypotenuse
cos α = -5/13

Determine ratio of ∠β
sin β = -1/2
sin β = sin 210° (third quadrant)
β = 210°

cos \beta = -\frac{1}{2}  \sqrt{3}

tan \beta= \frac{1}{3}  \sqrt{3}

SECOND PART
Solve the questions
Find sin (α + β)
sin (α + β) = sin α cos β + cos α sin β
sin( \alpha + \beta )=(- \frac{12}{13} )( -\frac{1}{2}  \sqrt{3})+( -\frac{5}{13} )( -\frac{1}{2} )
sin( \alpha + \beta )=(\frac{12}{26}\sqrt{3})+( \frac{5}{26} )
sin( \alpha + \beta )=(\frac{5+12\sqrt{3}}{26})

Find cos (α - β)
cos (α - β) = cos α cos β + sin α sin β
cos( \alpha + \beta )=(- \frac{5}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{12}{13} )( -\frac{1}{2} )
cos( \alpha + \beta )=(\frac{5}{26} \sqrt{3})+( \frac{12}{26} )
cos( \alpha + \beta )=(\frac{5\sqrt{3}+12}{26} )

Find tan (α - β)
tan( \alpha - \beta )= \frac{ tan \alpha-tan \beta }{1+tan \alpha  tan \beta }
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3}   }{1+(\frac{5}{12}) ( \frac{1}{2} \sqrt{3})}

Simplify the denominator
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3}   }{1+(\frac{5\sqrt{3}}{24})}
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }

Simplify the numerator
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{6}{12} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }
tan( \alpha - \beta )= \frac{ \frac{5-6\sqrt{3}}{12} }{ \frac{24+5\sqrt{3}}{24} }

Simplify the fraction
tan( \alpha - \beta )= (\frac{5-6\sqrt{3}}{12} })({ \frac{24}{24+5\sqrt{3}})
tan( \alpha - \beta )= \frac{10-12\sqrt{3} }{ 24+5\sqrt{3}}

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Answer:

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Step-by-step explanation:

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