The revenue in the problem is equal to $400 that is to be made out of 100 books selling at $8 each. The minimum number of books he has to seel is $400/$8 per book of 50 books. The maximum number is 100 books. Hence the answer to this problem is 50 ≤ x ≤ 100.
Step-by-step explanation:
The revenue in the problem is equal to $400 that is to be made out of 100 books selling at $8 each. The minimum number of books he has to seel is $400/$8 per book of 50 books. The maximum number is 100 books. Hence the answer to this problem is 50 ≤ x ≤ 100.
