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2 years ago

What is a equivalent expression to 4(5t - 7)

Mathematics

1 answer:

Ipatiy [6.2K]2 years ago

4 0

Answer:

20t-28

Step-by-step explanation:

expand the bracket

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Need answer quick please answer

lisov135 [29]

Answer: 24.96

Step-by-step explanation: just multiply them together

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2 years ago

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Kiran read for x minutes, and Andre read for 5/8 more than that. Write an equation that relates the number of minutes Kiran read

Liula [17]

Answer: $y = 1.625 x$

Step-by-step explanation:

Here x represents the time taken by Kiran in reading (in minutes) and y represents the time taken by Andrew in reading (in minutes).

According to the question,

Andre read for 5/8 more than kiran.

Thus, The time taken by Andrew(in minutes) = time taken by kiran + 5/8 of time taken by kiran

= $x + \frac{5}{8}\times x$

= $\frac{8}{8} + \frac{5}{8}$

= $\frac{13x}{8}$

= $1.625 x$

Thus, required equation,

$y = 1.625 x$

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3 years ago

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The equation A = (x)(x - 2) describes the area, A, of a triangular sand box, where x is the length of the base in feet. What wou

anyanavicka [17]

Answer is A number 2

7 0

2 years ago

Simplify the expression. Assume that all variables represent nonzero real numbers.StartFraction (4 n Superscript 4 Baseline q Su

Alja [10]

Answer:

$\frac{ - 3}{ 256 {q}^{10} {n}^{8} }$

Step by step explanation:

$\frac{ {(4 {n}^{4} {q}^{5})}^{2} {(8 {n}^{4} q)}^{-2} }{ {(- 3 {nq}^{9})}^{ - 1} {(4 {n}^{3} {q}^{9}) }^{3} }$

first we will change the terms with negative superscrips to the other side of the fraction

$\frac{{(4 {n}^{4} {q}^{5})}^{2}{(- 3 {nq}^{9})}^{ 1}}{{(4 {n}^{3} {q}^{9})}^{3} {(8 {n}^{4} q)}^{2} }$

then we will distribute the superscripts

$\frac{ {4}^{2} {n}^{2 \times 4} {q}^{2 \times 5} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{3 \times 3} {q}^{9 \times 3} {8 }^{2}{n}^{4 \times 2} {q}^{2} }$

$\frac{ {4}^{2} {n}^{8} {q}^{10} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{9} {q}^{27} {8 }^{2}{n}^{8} {q}^{2} }$

as when multiplying two powers that have the same base, we can add the exponents and, to divide podes with the same base, we can subtract the exponents

${4}^{2 - 3} {q}^{10 + 9 - 2 - 27} {n}^{8 + 1 - 8 - 9} {8}^{ - 2} { (- 3)}^{1}$

${4}^{ - 1} {q}^{ - 10} {n}^{ - 8} {8}^{ - 2} { (- 3)}^{1}$

then we will change again the terms with negative superscrips to the other side of the fraction

$\frac{ - 3}{ 4 \times {8}^{2} {q}^{10} {n}^{8} }$

$\frac{ - 3}{ 256 {q}^{10} {n}^{8} }$

4 0

2 years ago

PLZ HELP 20 POINTS I really need help and show the work if you got it right cause i want to know

Alex_Xolod [135]

Idek how they got that , but yk when you got it wrong you could see how to get the answer, you have check answers right?

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2 years ago