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Nadusha1986 [10]
3 years ago
11

Please help asap!!!!

Mathematics
1 answer:
Juliette [100K]3 years ago
8 0

Answer:

bbbbbbbbbbbbbbbbbbbbbbb

Step-by-step explanation:

bbbbbbbbb

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PLEASE HELP ME!!!1 <br> What is the value of x?<br><br><br><br> Enter your answer in the box.
pickupchik [31]
2x+2=3x-52
-x=-54
x=54
4 0
3 years ago
Mrs Johnson has $110 to spend on parking will cost $12 and admission tickets will cost $140 per person including tax
Vaselesa [24]

<em>The answer is Ms Hernandez can bring up to 6 people to the zoo.</em>

<em />

<em>x -  the number of people that she can bring to the zoo</em>

<em>The parking will cost $7: a = 7</em>

<em>Admission tickets will cost $15.50 per person: b = 15.50x</em>

<em>She can spend on parking and admission tickets $100:</em>

a + b ≤ 100

a = 7

b = 15.50x

7 + 15.50x ≤ 100

15.50x ≤ 100 - 7

15.50x ≤ 93

x ≤ 93 / 15.50

x ≤ 6

5 0
4 years ago
Loren solved the equation 10 = StartFraction 19 Over 9 EndFraction (149) + b for b as part of her work to find the equation of a
Elden [556K]

The error that Loren made is C. She should have solved 149 = StartFraction 19 Over 9 EndFraction (10) + b for b.

<h3>What is an equation?</h3>

It should be noted that an equation is a statement that shows that two mathematical expressions are equal.

In this case, for Loren to find the slope, this will be:

m = y2 - y1/x2 - x1

= (149 - 130)/(10 - 1)

= 19/9

In this case, the error that Loren made is that she should have solved 149 = StartFraction 19 Over 9 EndFraction (10) + b for b.

Learn more about equations on:

brainly.com/question/13763238

#SPJ1

5 0
2 years ago
The equation for the motion of an object with constant acceleration is d=vt+0.5at² where d is distance traveled in ft, v is star
sasho [114]

The expression for the distance the car travels after t seconds is d = 200t + 50t²

<h3>Equation of motion </h3>

From the question, we are to write an expression for the distance the car travels after t seconds

From the given information,

The equation for the motion of an object with constant acceleration is

d = vt + 0.5at²

For the race car,

v = 200 ft/s

a = 100 ft/s²

Putting the parameters into the equation, we get

d = 200t + 0.5(100)t²

d = 200t + 0.5 ×100)t²

d = 200t + 50t²

Hence, the expression for the distance the car travels after t seconds is d = 200t + 50t²

Learn more on Equations of motion here: brainly.com/question/20910641

#SPJ1

3 0
2 years ago
What is the constant for 5c2+7d
Julli [10]

Answer:

2

Step-by-step explanation:

5 and 7 are the coefficients if you need them

8 0
3 years ago
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