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xz_007 [3.2K]
2 years ago
14

If £2000 is placed into a bank account that pays 3% compound interest per year, how much will be in the account after 2 years?

Mathematics
2 answers:
gregori [183]2 years ago
7 0

Answer:

we gotta find compound amount here..

CA=compound amount

P=principal

R=rate of interest

T=time

Radda [10]2 years ago
4 0
£2090.9 there will be that amount in the account in 2 years
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If james is starting to save $150 to buy a new cell phone. In January he saved $5. In February he saved twice as much as he save
Anna [14]

Answer:

  • May

Step-by-step explanation:

March end is 15*2=30+15 =45

April 45*2=90+45=135

By may james will have enough money for phone

5 0
3 years ago
PLEASE HELP
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Answer:

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Step-by-step explanation:

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2 years ago
Can you guys help me with integers it these four problems for the first image do 18 and 19 for the second it’s 7 and 11 please h
xxMikexx [17]

Answer:

18. 20,000.

19. 0

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11. 101

Step-by-step explanation:

18. I think is stays the same, because an integer is a number that is not a fraction. So still 20,000.

19. Sea level is at zero altitude. So answer is 0.

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3 years ago
Raise aquarium is 20 inches long 20 inches wide and has a height of 15 inches Randles aquarium is 40 inches long 12 inches wide
Westkost [7]
Raise aquarium is 6000 inches
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4 0
3 years ago
PLEASE HELP ON #3 ASAP!
IrinaK [193]

9514 1404 393

Answer:

  1a: x+3 = 5

  1c: 6 = 2z

  2b: x = 2

  2d: 3 = z

  3: the solutions make the hangars balance

Step-by-step explanation:

1. We can write the equations by listing the contents of the hangar and using an equal sign to show the balance between left side and right side. It can work well to put left side contents of the hangar on the left side of the equal sign.

  A: x + 3 = 5

  C: 1 + 1 + 1 + 1 + 1 + 1 = z + z  simplifies to  6 = 2z

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2. B: We can subtract 3 from both sides of the hangar (and equation) to find the value of x.

  (x +3) -3 = 5 -3

  x = 2 . . . . . hangar balances with 2 on the right

D: We can divide both sides of the hangar by 2, splitting the content into two equal parts. Then one of those parts can be removed from each side.

  2(3) = 2(z)

  3 = z . . . . . . hangar balances with 3 on the left

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3. The found values will keep the hangar in balance when they are substituted for the corresponding variables.

  A: 2 + 3 = 5

  C: 1 + 1 + 1 + 1 + 1 + 1 = 3 + 3

4 0
3 years ago
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