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sveta [45]
3 years ago
6

5)

Mathematics
1 answer:
Tom [10]3 years ago
5 0

Answer:

is number one ka matalab hindi me janiye to the meeting ko join date puchhrahai hai ki tum mere ko bohot achhi lagi aur attitude to nahin hai ki tum mere ko bohot achhi lagi aur attitude to nahin hai ki tum mere ko bohot achhi lagi aur attitude to nahin hai ki tum mere ko bohot achhi lagi aur attitude to nahin hai ki tum mere ko bohot achhi lagi aur attitude to nahin hai ki tum mere ko bohot achhi lagi aur attitude to

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Side MN = 6, side OM = 9, side PQ = 6, and side RP = 9. What side corresponds to side NO and can be used to show that ΔMNO ≅ ΔPQ
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The useful life of an electrical component is exponentially distributed with a mean of 1000 hours a. What is the probability the
julia-pushkina [17]

Answer:

0.865

Step-by-step explanation:

To solve for the probability we would be using the formula:

F(x) = 1 - e^−λx

Therefore, P(x > 2000) = F(x) = 1 - e^−λx

Mean = 1000 hours

λ = 1/mean = 1/1000 hours

x= 2000 hours

F(x) = 1 - e^−(1/1000)2000

F(x) = 1 - e^−2

= 0.8646647168

Therefore, the probability the the circuit will last at least 2000 hours = 0.865

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3 years ago
I'm having trouble with this, it's geometry. please help and break it down if you can​
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