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nasty-shy [4]
2 years ago
10

F(x)=3x-2 find each value. F(3)

Mathematics
1 answer:
4vir4ik [10]2 years ago
4 0

Answer:

f(3) = 7

Step-by-step explanation:

Given:

f(x) = 3x -2

Evaluating f(3):

f(3) = 3(3) -2 \\ f(3) = 9 -2 \\ f(3) = 7

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Can someone help me answer this question ( moderators this is not a copy, the other ones got erased so go away)
Rainbow [258]
Triangles ABC and ADE are similar triangles. That means the sides are all scaled by the same factor.

To go from side BC to side DE, you multiply by 1.25. That means 1.25 is your scale factor. Now apply that factor to the bottom side to get your answer.

Side AB is 6. That means side AD is 6 x 1.25 = 7.5. That means x = 7.5 - 6 = 1.5
6 0
3 years ago
Given the Arithmetic sequence A1,A2,A3,A4A1,A2,A3,A4
Bad White [126]
The given sequence is
a₁ = 29
a₂ = 39
a₃ = 49
a₄ = 59

This sequence is an arithmetic sequence. Th first term is a₁ = 29, and the common difference is d= 10.

The n-th term is
a_{n}=a_{1}+(n-1)d
The 33-rd termis
a₃₃ = 29 + (33 - 1)*10
     = 29 + 320
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Answer: a₃₃ = 349
7 0
3 years ago
Solve: x^+4/x-1 = 5/x-1
AlexFokin [52]
The first step for solving this equation is to determine the defined range.
\frac{ x^{4}  }{x-1} = \frac{5}{x-1}, x ≠ 1
Remember that when the denominators of both fractions are the same,, you need to set the numerators equal. This will look like the following:
x^{4} = 5
Take the root of both sides of the equation and remember to use both positive and negative roots.
x +/- \sqrt[4]{5}
Separate the solutions.
x = \sqrt[4]{5}           , x ≠ 1
x = -\sqrt[4]{5} 
Check if the solution is in the defined range.
x = \sqrt[4]{5} 
x = -\sqrt[4]{5} 
This means that the final solution to your question are the following:
x = \sqrt[4]{5}          
x = -\sqrt[4]{5} 
Let me know if you have any further questions.
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7 0
3 years ago
The figure shows a parallelogram inside a rectangle outline: A parallelogram is shown within a rectangle. The length of the rect
Dominik [7]

Answer=5/16 or 0.3125 feet

Step-by-step explanation:

7 0
3 years ago
7 1/6 = 5 2/5 + p<br><br> p = ???
Crank

\huge\textbf{Hey there!}

\mathbf{7\dfrac{1}{6} = 5\dfrac{2}{5} + p}

\rightarrow\mathbf{7 \dfrac{1}{6} = 5\dfrac{2}{5} + p}

\mathbf{\rightarrow p + 5\dfrac{2}{5}= 7\dfrac{1}{6}}

\mathbf{\rightarrow {p + \dfrac{27}{5}=\dfrac{43}{6}}}

\text{SUBTRACT }\rm{\dfrac{27}{5}}\text{ to BOTH SIDES}

\mathbf{p + \dfrac{27}{5} - \dfrac{27}{5} = \dfrac{43}{6}- \dfrac{27}{5}}

\text{CANCEL out: }\rm{\dfrac{27}{5} - \dfrac{27}{5}}\text{ because it gives you 0}

\text{KEEP: }\rm{\dfrac{43}{6} - \dfrac{27}{5}}\text{ because it help solve for the p-value}

\text{NEW EQUATION: }\rm{p = \dfrac{43}{6} - \dfrac{27}{5}}

\large\textsf{SIMPLIFY IT!}

\mathbf{p = \dfrac{53}{30} \approx p = 1\dfrac{23}{30}}

\huge\boxed{\textsf{Therefore, your answer is: \boxed{\mathsf{p = 1\dfrac{23}{30}}}}}\huge\checkmark

\huge\textbf{Good luck on your assignment \&}\\\huge\textbf{enjoy your day!}

~\frak{Amphitrite1040:)}

3 0
2 years ago
Read 2 more answers
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