Answer:
<h3>Hence required integers are 11 and 13</h3>
Let x an odd positive integer
Then, according to question
x^2 +(x+2)^2=290
2x^2 +4x−286=0
x^2 +2x−143=0
x ^2+13x−11x−143=0
(x+13)(x−11)=0
x=11 as x is positive
Hence required integers are 11 and 13
Step-by-step explanation:
Hope it is helpful....
2x - 17?
= -17 +2x (using commutative property of addition, changing order and sum remains the same)
answer is A) -17 + 2x
What is the question ill try to help
1/2 &50 0.5 hope this helps
The Answer of <span>−2cos2π91 =</span> is -2
