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iren2701 [21]
2 years ago
6

( a-8) x b^3 Answer this

Mathematics
1 answer:
VARVARA [1.3K]2 years ago
5 0

Answer:

ab^3x - 8b^3x

Step-by-step explanation:

(a - 8)b^3x

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An equation and the steps to solve it are shown below:
Sphinxa [80]
S1: 7x - 4x - 2 = 6 OK
S2: 3x - 2 = 6 OK
S3: 3x - 2 + 2 = 6 WRONG, correct is 3x - 2 + 2 = 6 + 2

Answer: c. Step 3, because a number has been added only to one side of the equation.
6 0
3 years ago
What is 1/6 divided by 4​
Ksju [112]

Answer: 1/24 or 0.0416

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A shop sells chocolate, vanilla and strawberry ice cream cones. In one day, 45% of the ice cream cones sold are vanilla and 17%
True [87]

Answer:

950

Step-by-step explanation:

As, 45% will be vanilla, and 17% will be strawberry

So chocolate will be = 38%

As, 45%+17%+38% = 100%

So 38% of 2,500 = chocolate cones

= 38/100 x 2,500 = 950

So the number chocolate ice cream cone sold is 950.

8 0
2 years ago
The function f(x) = −x^2 − 5x + 50 shows the relationship between the vertical distance of a diver from a pool's surface f(x), i
pychu [463]
Set the function to equal zero:

-x^2 - 5x + 50 = 0

To find the zeros, or solutions, to this problem, we will use the quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Plug the values into the equation:

a = -1, b = -5, c = 50

x=\frac{5\pm\sqrt{-5^2-4(-1)(50)}}{2(-1)}

x=\frac{5\pm\sqrt{25+200}}{-2}

x=\frac{5\pm15}{-2}

Solve for both plus and minus:

\frac{5 + 15}{-2} = \frac{20}{-2} = -10

\frac{5 - 15}{-2} = \frac{-10}{-2} = 5

x = -10, x = 5

The question cannot use a negative value for x, as the diver cannot dive a negative distance from the board.

The answer is '<span>x = 5; the diver hits the water 5 feet away horizontally from the board', because x represents the horizontal distance away from the board.</span>
4 0
3 years ago
Alguien puede ayudarme en esto
Montano1993 [528]
Lo siento, español no es mi primer lengua, pero trataré ayudar. ¿Qué significa L1, L2, y L3? No recuerdo.
Necesita multiplicar
x-3 • x+2
x-2 • x-1
Pero, obtendrías esto, y no ayudaría
x^2-6 = x^2+2
Es imposible resolver para x con eso.
Creo que la respuesta es e. no existe tal valor para x

7 0
3 years ago
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