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pashok25 [27]
3 years ago
13

A phone company offers two monthly charge plans. In Plan A, the customer pays a monthly fee of and then an additional cents per

minute of use. In Plan B, the customer pays a monthly fee of and then an additional cents per minute of use. For what amounts of monthly phone use will Plan A cost less than Plan B? Use for the number of minutes of phone use, and solve your inequality for .
Mathematics
1 answer:
cluponka [151]3 years ago
3 0

Plan A: y = 25 + .06m

Plan B: y = 29.70 + .05m

25 + .06m < 29.70 + .05m

.01m < 4.7

m < 470 minutes

Hope this helps!

:D

From Kenny

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Nikitich [7]
They’re equivalent because 3 • 3 is 9 and whatever you do to the top, you do to the bottom, therefore 4 • 3 is 12. That would equal 9/12.
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3 years ago
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For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

Let w be the cost of the workshop hours

Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

12l=528-30w equation (5)

Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



3 0
3 years ago
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Solve by graphing if possible: 12n² + 11 = 0
ioda

Answer:

No real solutions

Step-by-step explanation:

5 0
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hichkok12 [17]

Answer:

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Step-by-step explanation:

6y - 5z = -8 .......... Equation 1

3z = -6 ................... Equation 2

4x - 3y - 2z= 21...... Equation 3

<u>First solve for z in Equation 2</u>

That's

3z = - 6

Divide both sides by 3

<h3>z = - 2</h3>

Next substitute the value of z into Equation 1 in order to find y

We have

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3 0
3 years ago
I make $348 a week at my new job. what is my yearly salary?
rosijanka [135]

Answer:

$18,096 a year

Step-by-step explanation:

There are around 52 weeks in a year. You make $348 a week.

52 x 348 = $18,096

3 0
3 years ago
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