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DanielleElmas [232]
3 years ago
10

Simplify the trigonometric expression.

Mathematics
2 answers:
ryzh [129]3 years ago
6 0
1/(1+sin theta) + 1/(1-sin theta) 

THe answer is letter D. 2 sec^2 theta

Hope it help! Goodluck! 
Natasha_Volkova [10]3 years ago
5 0
First we are going to find the common denominator of both fractions. To do that, we are going to multiply their denominators:
(1+sin \alpha )(1-sin \alpha )=1-sin^2 \alpha

Now we can rewrite our expression using the common denominator:
\frac{1-sin \alpha }{1-sin^2 \alpha } + \frac{1+sin \alpha }{1-sin^2 \alpha} = \frac{2}{1-sin^2 \alpha}

Finally, we can use the trig identities: 1-sin^2 \alpha =cos^2 \alpha and sec \alpha = \frac{1}{cos \alpha } to simplify our trig expression:
\frac{2}{cos^2\alpha}=2sec^2 \alpha

We can conclude that the correct answer is the fourth one.
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What is the volume of a rectangular prism with length 7 cm, height 6 cm, and width 13 cm? V = l x w x h
frutty [35]
Hello!

The formula for volume of a rectangular prism is:

V = l × w × h

Sinxe we have all the dimensions of the rectangular prism, all we need to do is multiply them together to find the volume.

V = 7 × 13 × 6

V = 546

ANSWER:

The volume of the rectangular prism is 546 cenimetres cubed.

*Volume is always cubed so put a little 3 above cm!
3 0
3 years ago
I'm genuinely lost in any problems like this and my teachers are no help, I need help doing exponents in general, everything to
Stolb23 [73]

Answer:

See below.

Step-by-step explanation:

4)

So we have the expression:

(-6n^{-3})^2

We can use the power of a product property, where:

(ab)^n=a^n\cdot b^n

So:

=(-6)^2\cdot(n^{-3})^2

For the left, -6 squared is the same as -6 times -6. This equals positive 36.

For the right, we can use the power of a power property. The property says that:

(a^n)^k=a^{nk}

So:

(n^{-3})^2=n^{(-3)(2)}\\=n^{-6}

So, all together, we have:

=(-6)^2\cdot(n^{-3})^2\\=36n^{-6}

6)

We have the expression:

-\frac{3x^0}{x^4}

First, note that anything to the zeroth power (except for 0) is 1, thus, x^0 is also 1. Simplify:

=-\frac{3}{x^4}

And that's the simplest we can do :)

Notes for 6)

We <em>can</em> put the x^4 to the numerator. Recall that when you put an exponent to opposite side, you put a negative. In other words:

x^n=\frac{1}{x^{-n}}

And vice versa:

\frac{1}{x^{-n}}=x^n

So, we can write the above as:

=-\frac{3}{x^4}\\=-\frac{3}{x^{-(-4)}}\\=-3x^{-4}

However, traditionally, we want only positive exponents, so this wouldn't be correct.

4 0
4 years ago
Read 2 more answers
the table shows steves bank account summary fir a month. which two values could be the remaining two debts Chart Credit. $476.35
Lilit [14]
Can you make the question more clear
3 0
4 years ago
Use the laws of Sines and law of cosines to find missing dimensions​
Andrei [34K]

Answer:

A) ERROR

B) ∠C = 26°

Step-by-step explanation:

Houston, We have a problem!!! too much information

If we had a legit triangle, the law of sines would hold

19/sin138 = 8/sin20

  28.395 = 23.390

as this is NOT an equality, the triangle does not exist as described.

IF it did, we'd get different results depending on which set we used

∠F = 180 - 138 - 20 = 22°

Law of sines

19/sin138 = DE/sin22 ⇒ DE = 19sin22/sin138 = <u>10.63697...</u>

or

8/sin20 =  DE/sin22 ⇒ DE = 8sin22/sin20 = <u>8.762211...</u>

If we attempt to use Law of cosines

DE² = 19² + 8² - 2(19)(8)cos22 = <u>11.9639...</u>

so really none is correct because we attempt to use trig calculations to a non-triangle.

12) AC² = 15² + 19² - 2(15)(19)cos120

      AC = 29.51270...

29.51270 / sin120 = 15/sinC

C = arcsin(15sin120/29.51270) = 26.1142... <u>26°</u>

6 0
3 years ago
Read 2 more answers
in a school 60% of the total number of student are boys. if the number of girl is 500, how many student are there in the class​
Andreas93 [3]

Answer:

x=1250 students

Step-by-step explanation:

x= total amount of students

boys=60% of x

so left is 40% of girls given number is 500

so x=total number of boys+girls

X = (60/100)*X+500

X - (60/100)*X = 500

(40/100)*X = 500

X = (500*100)/40

x=1,250 students

7 0
3 years ago
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