Question

1/5 (4-3x) = 1/7 (3x - 4) pls solve

Answer 1

Answer:

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Answer 2

$\huge \boxed{\mathfrak{Question} \downarrow}$

• $\large\sf\frac{1}{5} (4 - 3x) = \frac{1}{7} (3x - 4)$

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\frac{1}{5} (4 - 3x) = \frac{1}{7} (3x - 4)$

Use the distributive property to multiply 1/5 by 4-3x.

$\frac{1}{5}\times 4+\frac{1}{5}\left(-3\right)x=\frac{1}{7}\left(3x-4\right)$

Multiply 1/5 and 4 to get 4/5.

$\frac{4}{5}+\frac{1}{5}\left(-3\right)x=\frac{1}{7}\left(3x-4\right)$

Multiply 1/5 and -3 to get -3/5.

$\frac{4}{5}+\frac{-3}{5}x=\frac{1}{7}\left(3x-4\right)$

Use the distributive property to multiply 1/7 by 3x-4.

$\frac{4}{5}-\frac{3}{5}x=\frac{1}{7}\times 3x+\frac{1}{7}\left(-4\right)$

Multiply 1/7 and 3 to get 3/7 & 1/7 × -4 to get -4/7.

$\frac{4}{5}-\frac{3}{5}x=\frac{3}{7}x-\frac{4}{7}$

Subtract $\frac{3}{7}x$ from both sides.

$\frac{4}{5}-\frac{3}{5}x-\frac{3}{7}x=-\frac{4}{7}$

Combine $-\frac{3}{5}x$ and $-\frac{3}{7}x$ to get $-\frac{36}{35}x$.

$\frac{4}{5}-\frac{36}{35}x=-\frac{4}{7}$

Subtract 4/5 from both sides.

$-\frac{36}{35}x=-\frac{4}{7}-\frac{4}{5}$

The least common multiple of 7 and 5 is 35. Convert -4/7 and 4/5 to fractions with denominator 35.

$-\frac{36}{35}x=-\frac{20}{35}-\frac{28}{35}$

Because $-\frac{20}{35}$ and $\frac{28}{35}$ have the same denominator, subtract them by subtracting their numerators.

$-\frac{36}{35}x=\frac{-20-28}{35}$

Subtract 28 from -20 to get -48.

$-\frac{36}{35}x=-\frac{48}{35}$

Multiply both sides by $-\frac{35}{36}$, the reciprocal of $-\frac{36}{35}$.

$x=-\frac{48}{35}\left(-\frac{35}{36}\right)$

Multiply $-\frac{48}{35}$ by $-\frac{35}{36}$ by multiplying the numerator by the numerator and the denominator by the denominator.

$x=\frac{-48\left(-35\right)}{35\times 36}$

Carry out the multiplications in the fraction $\frac{-48\left(-35\right)}{35\times 36}$.

$x=\frac{1680}{1260}$

Reduce the fraction 1680/1260 to its lowest terms by extracting and cancelling out 420.

$\huge \boxed{ \boxed{ \bf \: x=\frac{4}{3} \approx \: 1.33}}$