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madam [21]
4 years ago
12

Give the slope and y intercept 6x-3y=-9

Mathematics
1 answer:
Nikolay [14]4 years ago
5 0
To find the slope and the y-intercept of this equation, we need to first convert it to slope-intercept form. (y = mx + b)

To convert it, we need to first isolate the y term by subtracting 6x from both sides of the equation.

6x - 6x - 3y = -9 - 6x

-3y = -9 - 6x

Now that the y term is on one side of the equation, we can continue.

Divide <em>everything </em>on the left side of the equation by the coefficient on the right side of the equation. In this case, the number is 3.

y = -3 - 2x

Flip some of those numbers around to get this:

y = 2x - -3

Get rid of the double negative. (Change 2x - -3 into 2x + 3)

y = 2x + 3

Now that we've converted the equation, we can identify the slope (the number beside x) and y-intercept (the number that stands alone)

Slope: 2
Y-intercept: 3


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Answer:

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Step-by-step explanation:

3 0
4 years ago
Limit of x^2-81/x+9<br> As x goes toward -9
Semmy [17]
Hello,

Use the factoration

a^2 - b^2 = (a - b)(a + b)

Then,

x^2 - 81 = x^2 - 9^2

x^2 - 9^2 = ( x - 9).(x + 9)

Then,

Lim (x^2- 81) /(x+9)

= Lim (x -9)(x+9)/(x+9)

Simplity x + 9

Lim (x -9)

Now replace x = -9

Lim ( -9 -9)

Lim -18 = -18
_______________

The second method without using factorization would be to calculate the limit by the hospital rule.

Lim f(x)/g(x) = lim f(x)'/g(x)'

Where,

f(x)' and g(x)' are the derivates.

Let f(x) = x^2 -81

f(x)' = 2x + 0
f(x)' = 2x

Let g(x) = x +9

g(x)' = 1 + 0
g(x)' = 1

Then the Lim stay:

Lim (x^2 -81)/(x+9) = Lim 2x /1

Now replace x = -9

Lim 2×-9 = Lim -18

= -18




7 0
3 years ago
What is the equation of the line that passes through the point (6, 4) and has a slope<br> of - ?
Dafna1 [17]
Hey what’s the slope ?
4 0
4 years ago
what is 8+8? IM CRYING PLS. WILL GIVE BRAINLIEST. I DONT KNOW IVE BEEN UP ALL NIGHT STRESSING PLEASE.
Ahat [919]

Answer:

Hey buddy, here is your answer. Hope it helps you.

Step-by-step explanation:

8+8=16.

3 0
3 years ago
Read 2 more answers
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