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madam [21]
4 years ago
12

Give the slope and y intercept 6x-3y=-9

Mathematics
1 answer:
Nikolay [14]4 years ago
5 0
To find the slope and the y-intercept of this equation, we need to first convert it to slope-intercept form. (y = mx + b)

To convert it, we need to first isolate the y term by subtracting 6x from both sides of the equation.

6x - 6x - 3y = -9 - 6x

-3y = -9 - 6x

Now that the y term is on one side of the equation, we can continue.

Divide <em>everything </em>on the left side of the equation by the coefficient on the right side of the equation. In this case, the number is 3.

y = -3 - 2x

Flip some of those numbers around to get this:

y = 2x - -3

Get rid of the double negative. (Change 2x - -3 into 2x + 3)

y = 2x + 3

Now that we've converted the equation, we can identify the slope (the number beside x) and y-intercept (the number that stands alone)

Slope: 2
Y-intercept: 3


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sasho [114]
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x² + x = 7/4
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x = -b+/-√b² -4ac all of them divide by 2a
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4 0
4 years ago
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djverab [1.8K]

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5 0
3 years ago
Write the point-slope form of the equation of the line that passes through the points (6, -9) and (7, 1). Include your work in y
lys-0071 [83]
First find the slope, 
m=(y2-y1)/(x2-x1)=(1-(-9))/(7-6)=10
Next, use the point slope form to find the equation:
L : y-y1=m(x-x1) => y-1=10(x-7) 
    [in point slope form, point is (7,1), slope=m=10 ]


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3 years ago
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