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astra-53 [7]
3 years ago
8

The graph shows the proportional relationship between the pounds of bananas purchased, x,

Mathematics
1 answer:
bazaltina [42]3 years ago
3 0

Answer:

1. The point (3,1.80) represents that 3 bananas cost 1.80$. It costs .60$ per 1 lb of bananas

2. The point (6,3.60) represents that it costs 3.60$ per 6lbs of bananas

Step-by-step explanation:

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Llana [10]

<u>Answer:</u>

2x²+6x-9=0

<u>Step-by-step explanation:</u>

2x(3+x)=9

6x+2x²=9

2x²+6x-9=0

6 0
3 years ago
Sonny and logan where driving go carts around the track. Sony took 15 minutes to drive 1 lap, it took logan 9 minutes to drive a
tamaranim1 [39]

Answer:

45 minutes

Step-by-step explanation:

Let, after time t minutes, they meet again at the same point.

In time t minutes, let Sony completes x lap while Iogan completes y laps. Note that x and y must be the counting numbers.

As Sonny took 15 minutes to drive 1 lap, so,

t=15x\cdots(i)

While Iogan Sonny took 9 minutes to drive 1 lap, so,

t=9y

\Rightarrow 15x=9y [from equation (i)]

\Rightarrow \frac {x}{y}=\frac{9}{15}

\Rightarrow \frac {x}{y}=\frac{3}{5}

As x,y must be counting number, so

(x,y)=(3,5),(6,10),...,(3n,5n) where n is a positive integer.

So, the minimum number of laps required are

x=3 and y=5  (when they meet for the first time)

Now, from equation (i),

The time required to meet them for the first time, t=15x3=45 minutes.

7 0
4 years ago
For a class of students, the association between GPA and SAT math score is roughly linear. The
nordsb [41]

Answer:

612.44

Step-by-step explanation:

Given the linear regression equation between SAT score and GPA

y = 410.54 + 67.3x

Where

y = SAT math score ; x = GPA

THE SAT math score for Jessica who has a GPA of 3.00

x = 3

y = 410.54 + 67.3(3)

y = 410.54 + 201.9

y = 612.44

8 0
3 years ago
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bagirrra123 [75]

Answer:

Step-by-step explanation:

2 is =     1.15

3 0
3 years ago
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DENIUS [597]

Answer:

a^7/8^2

Step-by-step explanation:

Here, we want to write the expression using only positive exponents

An important rule for indices to use here is that;

a^-b = 1/a^b

thus;

8^-2 = 1/8^2

So we have;

1/8^2 * a^7

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8 0
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