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Kryger [21]
3 years ago
14

Here is 13 & 16 .. take you time :)

Mathematics
2 answers:
Serhud [2]3 years ago
7 0

Answer:

13) 1 Remove parentheses.

4

0.

×

4

−

3

4

0.

×4

−3

2 Use Negative Power Rule:

x

−

a

=

1

x

a

x

−a

=

x

a

1

​

.

4

0.

×

1

4

3

4

0.

×

4

3

1

​

3 Simplify

4

3

4

3

to

64

64.

4

0.

×

1

64

4

0.

×

64

1

​

4 Simplify.

4

0.

64

64

4

0

16) 6

0

6.

×2

6

2 Simplify

2

6

2

6

to

64

64.

0

6.

×

64

0

6.

×64

I hope this helps you

Aleks04 [339]3 years ago
3 0

Answer:

{4}^{0} . \:  \:   {4}^{ - 3}  \\  = {4}^{0 + ( - 3)}  \\  =  {4}^{ - 3}  \\  =  \frac{1}{ {4}^{3} }

{0}^{6} .  \:  \: {2}^{6}  \\  =  {0}^{6 + 6}  \\  =  {0}^{12}

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A circle has a radius of \sqrt{13}√ ​13 ​ ​​ square root of, 13, end square root units and is centered at (-9.3,4.1)(−9.3,4.1)le
timofeeve [1]

Answer:  The equation of the circle is

x^2+y^2+18.6x-8.2y+90.3=0.

Step-by-step explanation:  We are given to write the equation of the circle with radius √13 units and center at the point (-9.3, 4.1).

We know that

the standard equation of a circle with radius r units and center at the point (h, k) is given by

(x-h)^2+(y-k)^2=r^2.

In the given circle,

radius, r = √13 units  and  center, (h, k) = (-9.3, 4.1).

Therefore, the equation of the circle will be

(x-(-9.3))^2+(y-4.1)^2=(\sqrt{13})^2\\\\\Rightarrow (x+9.3)^2+(y-4.1)^2=13\\\\\Rightarrow x^2+18.6y+86.49+y^2-8.2y+16.81=13\\\\\Rightarrow x^2+y^2+18.6x-8.2y+103.3=13\\\\\Rightarrow x^2+y^2+18.6x-8.2y+90.3=0.

Thus, the equation of the circle is

x^2+y^2+18.6x-8.2y+90.3=0.

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