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Free_Kalibri [48]
4 years ago
7

Five times the difference between a number and four is greater than the quotient of four times the number and six. Find the smal

lest integer that will satisfy the inequality
Mathematics
2 answers:
JulijaS [17]4 years ago
8 0
x-\ number\\\\\
5(x-4)>\frac{4x}{6}\ \ \ | multiply\ by\ 6\\\\
30(x-4)>4x\\\\
30x-120>4x\ \ \ \ | subtract\ 4x\\\\
26x-120>0\ \ \ | add\ 120\\\\
26x>120\ \ \  | divide\ by\ 26\\\\
x>\frac{120}{26}\\\\
x>4\frac{8}{13}
Ray Of Light [21]4 years ago
7 0
5 times (5 times) the differnce (-) a number(x) and 4(4) is greater than (>) the quotient (/) 4 times the nmber (4x) and 6 (6)

5(x-4)>4x/6
5x-20>4x/6
treat > as an equals for nnow
multiply both sides by 6
30x-120>4x
divide both sides by 2
15x-60>2x
add 60 to both sides
15x>2x+60
subtract 2x from both sides
13x>60
divide both sdie sby 13
x>60/13
the smalles tnumber is the next number bigger then 60/13
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Which equation represents the line that is perpendicular to and passes through (-6,-9)?
Scilla [17]

Answer:

y = -9

Step-by-step explanation:

Complete question;

Which equation represents the line y = 1/4 that is perpendicular to and passes through (-6,-9)?

The equation of the line in point slope form is y-y0 = m(x-x0)

Given the equation y = 1/4, the slope of the line is zero

Substitute the slope and the point into the formula;

y -(-9) = 0(x-(-6)

y + 9 = 0

y = -9

Hence the required equation is y = -9

6 0
3 years ago
HELPPP!!
sdas [7]
SOLUTION:
 

A box has a square base of side x and height y where x,y > 0.
Its volume is V = x^2y and its surface area is S = 2x^2 + 4xy.
(a) If V = x^2y = 12, then y = 12=x^2 and S(x) = 2x^2 C 4x (12=x2) = 2x2 + 48x^-1. Solve S'(x) = 4x - 48x-2 = 0 to obtain x = 12^1/3. Since S(x/) ---> infinite as x ---> 0+ and as x --->infinite, the minimum surface area is S(12^1/3) = 6 (12)^2/3 = 31.45, when x = 12^1/3 and y = 12^1/3.


(b) If S = 2x2 + 4xy = 20, then y = 5^x-1 - 1/2 x and V (x) = x^2y = 5x - 1/2x^3. Note that x must lie on the closed interval [0, square root of 10]. Solve V' (x) = 5 - 3/2 x^2 for x>0 to obtain x = square root of 30 over 3 . Since V(0) = V (square root 10) = 0 and V(square root 30 over 3) = 10 square root 30 over 9 , the maximum volume is V (square root 30 over 3) = 10/9 square root 30 = 6.086, when x = square root 30 over 3 and y = square root 30 over 3 .
5 0
3 years ago
Charlotte used a calculator to subtract.
Sati [7]

Answer:

Step-by-step explanation:

1.  She omitted the 0 from the minuend, entering 24.59 instead of 204.59

2. She misplaced the decimal point of the minuend, entering 93.64 instead of 936.4

3. She typed 4 instead of 5 in the minuend, entering 46.3 instead of 56.3

4 0
3 years ago
6y-2x=20 so y =---/---- +-----/-----
azamat
I hope this helps you



6y-2x=20


2 (3y-x)=2.10


3y-x=10


3y=x+10


y=x+10/3
4 0
3 years ago
Read 2 more answers
Sheri is making 4 pounds of mixed nuts. She will use One-third the amount of macadamia nuts as she does almonds. A graph titled
notsponge [240]

1 pound of macadamia nuts; 3 pounds of almonds of each nut will she use.

Given that,

Sheri is making 4 pounds of mixed nuts.

She will use One-third the number of macadamia nuts as she does almonds.

A graph titled Sheri's mixed nut recipe has pounds of macadamia nuts on the x-axis, and pounds of almonds on the y-axis. 2 lines intersect at (1, 3).

We have to find,

How many pounds of each nut will she use?

According to the question,

Total mixed nuts are 4 pounds,

She will use One-third the number of macadamia nuts as she does almonds.

2 lines intersect at (1, 3).

Therefore,

Sheri's mixed nut recipe has pounds of macadamia nuts on the x-axis,

At x-axis, the point 1 lies.

So, macadamia nuts have 1 pound.

And pounds of almonds on the y-axis,

At y-axis, the point 3 lies.

So, almond nuts have 3 pounds.

Hence, 1 pound of macadamia nuts; 3 pounds of almonds of each nut will she use.

For more details about Graphs refer to the link given below.

brainly.com/question/9351049

8 0
3 years ago
Read 2 more answers
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