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larisa [96]
3 years ago
8

Hey Guys :PWhat's Going On

="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
dem82 [27]3 years ago
5 0

Answer:

Anybody reading this should know that I hope you have a beautiful day!

Gala2k [10]3 years ago
5 0

Answer:

Ummm.. hey?

Pretty much nothing... so yeah...

AnimeVines

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Express in scientific notation 1,789
SVEN [57.7K]

Answer:

1.789*10^{3}

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3 years ago
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The figure shows a carpeted room. How many square feet of the room are carpeted?
Nadya [2.5K]

Answer:

Hello there, the answer would be

Step-by-step explanation:

We cut the figure into two different shapes.

Since on one side it is 4 feet and the height is seven, we cut right there.

So the bottom figure is now 4 x 5 = 20

The top figure is cut with 3 height left, So all we do is just multiply.

8 x 3 = 24.

20+24=44.

PLEASE MARK AS BRAINLIEST!!!

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Giving brainliest and thanks
lisabon 2012 [21]

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23 tallys all you need to do (form what i was taught ) is add up all the tallys

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3 years ago
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Bethany s making trail mix with 3 cups of raisins for every 2 cups of peanuts
DaniilM [7]

Answer:

4 cups of raisins

3 cups of dates

6 cups of peanuts

and 2 cups of cashews

ratio cashews to raisins= 2:4

                                      = 1:2

ratio dates to peanuts= 3:6

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5 0
4 years ago
An on-the-job injury occurs once every 10 days on
ExtremeBDS [4]

The probability that the next on-the-job injury will occur within 10, 5, and 1 day are 0.632, 0.393, and 0.095

<h3>What is probability?</h3>

It is defined as the ratio of the number of favourable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

We know the exponential distribution is given by;

\rm P(X < t)=1-e^{-\dfrac{1}{\mu}t}

The probability that the next on-the-job injury will occur within 10 days:

\rm P(X < 10)=1-e^{-\dfrac{1}{10}10}

P(X< 10) = 0.632

The probability that the next on-the-job injury will occur within 20 days:

\rm P(X < 5)=1-e^{-\dfrac{1}{10}5}

P(X< 5) = 0.393

The probability that the next on-the-job injury will occur within 1 days:

\rm P(X < 1)=1-e^{-\dfrac{1}{10}1}

P(X< 1) = 0.095

Thus, the probability that the next on-the-job injury will occur within 10, 5, and 1 day are 0.632, 0.393, and 0.095

Learn more about the probability here:

brainly.com/question/11234923

#SPJ1

5 0
3 years ago
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