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Burka [1]
3 years ago
5

Determine the slope of the line that passes through the points (-4, 6) and (0, 4).

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0
Slope = rise/run = (change in y)/(change in x)
Slope = (4-6)/(0-(-4)) = (-2)/(4)
Slope = -1/2 = -0.5
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Please answer CORRECTLY for brainliest guarantee. If your answer is not correct or does not have a explanation I will report you
Scorpion4ik [409]

Answer:

c. 45.34ft

Step-by-step explanation:

When leg one of the triangle is 15ft and leg two is 17 ft you would take   17^2 + 15^2 and then you find the square root of that (514) to get the hypotenuse of the triangle. After that you multiply by two to account for the 2/2 sqaure foot per each unit

4 0
3 years ago
What is the answer x+5>23
olga2289 [7]
18<x is the answer you are looking for. Glad to help.
3 0
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Write the​ point-slope form of the line satisfying the given conditions. Then use the​ point-slope form of the equation to write
abruzzese [7]

slope = m = 16-10 / 8-5 = 6/3 = 2

y - y1 = m x (x-x1)

y-10 = 2 x (x-5)

y-10 = 2x-10

y = 2x


7 0
3 years ago
If x &gt; 0 and y &gt; 0, where is the<br> point (x, y) located?
Scrat [10]
  • Given, x > 0, y > 0.
  • So, the values of x and y are less than 0, that means, they are negative integers.
  • If we divide a Cartesian plane with the x-axis and y-axis, we get four quadrants.
  • 1st Quadrant : (+,+)
  • 2nd Quadrant : (-,+)
  • 3rd Quadrant : (-,-)
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  • Since the values of x and y are both negative, so (x, y) is located in the <em><u>3rd Quadrant</u></em>.

Hope you could get an idea from here.

Doubt clarification - use comment section

8 0
2 years ago
This bag has an unknown number of lollipops and jelly snakes in it. I know that Pr (jelly snake) = 4/5. How many jelly snakes co
juin [17]

Answer:

40.

Step-by-step explanation:

Let J represent jelly snake.

Let L represent lollipops

Let S represent sample space

Let y represent the number of jelly snake in the bag. I.e

Number of J = y

Number of L = 10

Number of S = 10 + y

From the question given, we were told that the probability of jelly snake P(J) is 4/5.

But probability of jelly snake, P(J) is given by:

P(J) = nJ/nS

nJ = y

nS = 10 + y

P(J) = 4/5

Thu, we can obtain the number jelly snake, y, in the bag as follow:

P(J) = nJ/nS

4/5 = y/(10 + y)

Cross multiply

5y = 4(10 + y)

Clear bracket

5y = 40 + 4y

Collect like terms

5y – 4y = 40

y = 40

Therefore, the number of jelly snake in the bag is 40

8 0
3 years ago
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