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frozen [14]
3 years ago
9

AQuestion 4 of 10 What is the simplified form of the fraction below? 14/49 A.1/7

Mathematics
2 answers:
Volgvan3 years ago
8 0

Answer:

2/7

Step-by-step explanation:

14 divided by 7= 2

49 divided by 7=7

the answer is 2/7

ad-work [718]3 years ago
6 0
2/7 is the simplest of fraction
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Evelyn saves 40% of her earnings for college. This year, she earned $200 more than last
N76 [4]

Answer:

$ 2,050

Step-by-step explanation:

Earnings last year : x

0.4(x + 200) = 900

(x + 200) =900/0.4

x + 200 = 2250

x = 2250 - 200

x = $2,050

6 0
3 years ago
Suppose an airline accepted 12 reservations for a commuter plane with 10seats. They know that 7 reservations went to regular com
kvv77 [185]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

7 persons will show up for sure, hence there is not any kind of probability here.

The other 5 persons have 50% chance to show up.

The flight will be overbooked, if either 4 will come or 5 will come.

From the total 5 persons, 4 can be chosen in ^5C_4 = 5 ways.

The probability that any four among the 5 will come is 5\times(\frac{50}{100} )^{5} = 5\times(\frac{1}{2} )^{5} = \frac{5}{32}.

The probability that all of the 5 passengers will come is \frac{1}{32}.

Hence, the required probability is \frac{5}{32} + \frac{1}{32} = \frac{6}{32} = \frac{3}{16}.

(b)

The probability that there will be exactly 10 passengers on the flight is ^5C_3\times (\frac{1}{2} )^5 = \frac{20}{2} \times\frac{1}{32} = \frac{10}{32} = \frac{5}{16}.

The probability that there will be no empty seats in the plane is \frac{3}{16} + \frac{5}{16} = \frac{1}{2}.

Hence, probability of having empty seats is 1 - \frac{1}{2} = \frac{1}{2}.

6 0
3 years ago
If tanA+sinA=m and tanA-sinA=n.prove that m^2-n^2=4√mn
mash [69]

Let a=\tan A and b=\sin A. Then

m^2-n^2=(a+b)^2-(a-b)^2=(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab

\implies m^2-n^2=4\tan A\sin A

and

mn=(a+b)(a-b)=a^2-b^2

\implies4\sqrt{mn}=4\sqrt{\tan^2A-\sin^2A}

The expression under the square root can be rewritten as

\tan^2A-\sin^2A=\dfrac{\sin^2A}{\cos^2A}-\sin^2A=\sin^2A\left(\dfrac1{\cos^2A}-1\right)=\sin^2A(\sec^2A-1)

Recall that

\sin^2A+\cos^2A=1\implies\tan^2A+1=\sec^2A

so that

\tan^2A-\sin^2A=\sin^2A\tan^2A

and assuming \sin A>0 and \tan A>0, we end up with

4\sqrt{\tan^2A-\sin^2A}=4\tan A\sin A

so that

m^2-n^2=4\sqrt{mn}

as required.

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2 years ago
Plz help me on this question
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3 years ago
Which image shows a translation?<br> А<br> B<br> с
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