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3 years ago

15

Solve: r5 - 6 = -1 A) r = 1 B) r = 5 C) r = 10 D) r = 25

1 answer:

Andre45 [30]3 years ago

3 0

Answer:

1

Step-by-step explanation:

1 ×5-6=-1 Define this stuff is really easy are you going to do is look at all the options that they have there for our and fill in for our or whichever one works will equal to -1 so in this case the one that works is -1 Sol is think about it all you got to do is just fill it in like they give an example ours and they gave us a question or sequel to one just put one size 5 - 6 is equal to -1 -1 is what you trying to get

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A list of numbers is given <br><br><br> 32,16,8,4,2,1<br><br> Write a rule for the pattern

Sphinxa [80]

It is subtracting the current number by 1/2 OR you can divide by 2. each time.

32 / 2= 16
16 / 2=8
8/2=4
4/2=2
2/2=1

Hope this helped!

5 0

3 years ago

Read 2 more answers

If you can solve it.Thanks in advance

vivado [14]

Answer:

$f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}$

Step-by-step explanation:

we have

$f(x)=x^{2} +\frac{1}{\sqrt[3]{x}}$

$g(x)=\frac{1}{x^{2}+1}$

we know that

In the function

$f(g(x))$

The variable of the function f is now the function g(x)

substitute

$f(g(x))=(\frac{1}{x^{2}+1})^{2} +\frac{1}{\sqrt[3]{(\frac{1}{x^{2}+1})}}$

$f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}$

4 0

3 years ago

What are the solutions of the equation x^4-9x^2+8=0? Use u substitution to solve.

vodka [1.7K]

Answer:

The answer is the second option

Step-by-step explanation:

Let u=x^2.

$( {x}^{2} ) {}^{2} - 9( {x}^{2} ) + 8( {x}^{2} ) {}^{0}$

${u}^{2} - 9u + 8$

$(u - 1)(u - 8)$

$u = 1$

$u = 8$

Set this equal to x^2

${x}^{2} = 1$

$x = 1$

or

$x = - 1$

${x}^{2} = 8$

$x = 2 \sqrt{2}$

or

$x = - 2 \sqrt{2}$

4 0

2 years ago

Explain how an estimate helps you to place the decimal point when multiplying 3.9x5.3

Pepsi [2]

When you estimate, you round the decimal up.3.9 rounds up to 4 ,5.3 rounds up to 5.

4 times 5 equals 20.The actual answer is 20.67.

5 0

3 years ago

Find dy/dx using first principle<br>x+1/x

JulsSmile [24]

Answer:

The derivative of the function is:

$f'(x)=1-\frac{1}{x^{2}}$

Step-by-step explanation:

The first principle is given by:

$f'(x)=\frac{dy}{dx}=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

The function here is:

$f(x)=x+\frac{1}{x}$

Now, using the first principle we have:

$f'(x)=lim_{h\rightarrow 0}\frac{(x+h)+\frac{1}{(x+h)}-x-\frac{1}{x}}{h}$

$=lim_{h\rightarrow 0}\frac{h+\frac{1}{(x+h)}-\frac{1}{x}}{h}$

$=lim_{h\rightarrow 0}\frac{h-\frac{h}{x(x+h)}}{h}$

$=lim_{h\rightarrow 0}\frac{h(1-\frac{1}{x(x+h)})}{h}$

$=lim_{h\rightarrow 0}1-\frac{1}{x(x+h)}$

$=1-\frac{1}{x^{2}}$

Therefore, the derivative of the function is:

$f'(x)=1-\frac{1}{x^{2}}$

I hope it helps you!

6 0

3 years ago